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Leto [7]
1 year ago
12

Ms. Cassidy plotted the point (2, 3) on Miguel’s graph of y < 2x – 4. She instructed him to change one number or one symbol i

n his inequality so that the point (2, 3) can be included in the solution set. Which equations might Miguel write? Check all that apply
Mathematics
2 answers:
elixir [45]1 year ago
5 0

Answer:

C, D,F

Step-by-step explanation:

Mademuasel [1]1 year ago
3 0

Answer:

Its C

Step-by-step explanation:

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Aubrey and Charlie are driving to a city that is 120 miles from their house. They have already traveled 20 miles, and they are d
mario62 [17]

Answer:

f(1.5) = _95_

The value indicates that after_1.5 hours_

hours of driving, Aubrey and Charlie will be_95_

miles from home.

Step-by-step explanation:

8 0
1 year ago
A wedding planner purchased small and large lanterns for a wedding reception. The small lanterns cost $25 each, and the large la
Marina CMI [18]
Answer: y=12 x=28

Explanation:
x=Amount of Small Lanterns y=Amount of Large Lanterns
25x+40y=1180
x+y=40
x=40-y
25(40-y)+40y=1180
1000-25y+40y=1180
1000+15y=1180
15y=180
y=12
x+12=40
x=28
5 0
2 years ago
Read 2 more answers
A pair of pants costs twice as much as a shirt. The total cost of 1 pair of pants and 1 shirt is $18 . If s represents the cost
dolphi86 [110]

Let the price of 1 shirt be represented by = s

A pair of pants costs twice as much as a shirt, then the cost of pants is = 2s

The total cost of 1 pair of pants and 1 shirt is $18 , means : s+2s=18

Solving this we get,                            

3s=18

s=6

So, the price of 1 shirt is $6 and price of 1 pair of pants is = 2s = 2*6 = $12.

8 0
2 years ago
Read 2 more answers
Line segment JL is an altitude in triangle JKM. Which statement explains whether JKM is a right triangle? Round measures to the
natulia [17]

Answer:

C. JKM is not a right triangle because KM ≠ 15.3.

Step-by-step explanation:

We can see from our diagram that triangle JKM is divided into right triangles JLM and JLK.  

In order to triangle JKM be a right triangle KM^{2}=JK^{2}+JM^{2}.

We will find length of side KM using our right triangles JLM and JLK as KM=KL+LM.  

Using Pythagorean theorem in triangle JLM we will get,

LM=\sqrt{JM^{2}-JL^{2}}

LM=\sqrt{8^{2}-5^{2}}

LM=\sqrt{64-25}

LM=\sqrt{39}=6.244997998\approx 6.24

Now let us find length of side KL.

KL=\sqrt{JK^{2}-JL^{2}}  

KL=\sqrt{13^{2}-5^{2}}

KL=\sqrt{169-25}

KL=\sqrt{144}=12

Now let us find length of KM by adding lengths of KL and LM.

KM=12+6.24=18.24

Now let us find whether JKM is right triangle or not using Pythagorean theorem.

KM^{2}=JK^{2}+JM^{2}  

18.24^{2}=13^{2}+8^{2}

18.24^{2}=169+64

18.24^{2}=233

Upon taking square root of both sides of equation we will get,

18.24\neq 15.264337522473748

18.2\neq 15.3  

We have seen that KM equals 18.2 and in order to JKM be a right triangle KM must be equal to 15.3, therefore, JKM is not a right triangle and option C is the correct choice.    

6 0
1 year ago
Read 2 more answers
The number of airline passengers in 1990 was 466 million. The number of passengers traveling by airplane each year has increased
taurus [48]

Answer:

2010.

Step-by-step explanation:

We have been given an exponential growth formula P(t)=466\cdot 1.035^t, which represents number of passengers traveling by airplane since 1990.

To find the year in which 900 million passengers will travel by airline, we will equate the given formula by 900 and solve for t as:

900=466\cdot 1.035^t

\frac{900}{466}=\frac{466\cdot 1.035^t}{466}1.9313304721030043=1.035^t

Take natural log of both sides:

\text{ln}(1.9313304721030043)=\text{ln}(1.035^t)

Using property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

\text{ln}(1.9313304721030043)=t\cdot \text{ln}(1.035)

0.658209129198=t\cdot 0.034401426717

\frac{0.658209129198}{0.034401426717}=\frac{t\cdot 0.034401426717}{0.034401426717}

19.1331927775=t\\\\t=19.1331927775

This means that in the 20th year since 1990, 900 million passengers would travel by airline.

1990+20=2010

Therefore, 900 million passengers would travel by airline in 2010.

6 0
1 year ago
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