Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
To solve
82% of x = 119.31
rewrite
x = 119.31/0.82
solve
x <span>≈ 145.5</span>
Hope this helps :)
Alrighty, so, if I remember correctly: For the first question you have 20 possible outcomes, 4 of which are multiples of 5. (5,10,15,20). This gives you 4/20, I multiplied both the numerator and denominator by 200 which then gave me 800/4000. Next I divided which gave me 0.2.
Answer:
50y^4x/49
Step-by-step explanation:
y^3/98
((100* y^3/98 * x) * y
2.1 y^3 * y^1=y^(3+1)=y^4
Answer:
26
Step-by-step explanation:
Distance between (-2,5) and (-2,1) is 5
Distance between (-2,5) and (6,5) is 8
Distance between (6,5) and (6,1) is 5
Distance between (6,1) and (-2,1) is 8
5+8+5+8=26
