Question

Starting from rest, the boy runs outward in the radial direction from the center of the platform with a constant acceleration of 0.5 m/s2 . The platform rotates at a constant rate of 0.2 rad/s. Determine his velocity (magnitude) when t = 3 sec

Answer 1

Answer:

His velocity when t= 3 sec is V= 1.56 m/s

Explanation:

a= 0.5 m/s²

ω= 0.2 rad/s

t= 3 sec

Vr= a*t

Vr= 1.5 m/s

r= a*t²/2

r= 2.25m

Vt= w*r

Vt= 0.45 m/s

V= √(Vr²+Vt²)

V= 1.56 m/s