Given that,
Current = 4 A
Sides of triangle = 50.0 cm, 120 cm and 130 cm
Magnetic field = 75.0 mT
Distance = 130 cm
We need to calculate the angle α
Using cosine law
We need to calculate the angle β
Using cosine law
We need to calculate the force on 130 cm side
Using formula of force
We need to calculate the force on 120 cm side
Using formula of force
The direction of force is out of page.
We need to calculate the force on 50 cm side
Using formula of force
The direction of force is into page.
Hence, The magnitude of the magnetic force on each of the three sides of the loop are 0 N, 0.1385 N and 0.1385 N.
The resultant motion is given by pithagoras, since the two components (north and east) are perpendicular to each other.
They are asking you about the direction so you have to use trigonometry, finding that the direction is Ф=arctan(3.8/12)=17.57° north of east.
Answer:
Earth would continue moving by uniform motion, with constant velocity, in a straight line
Explanation:
The question can be answered by using Newton's first law of motion, also known as law of inertia, which states that:
"an object keeps its state of rest or of uniform motion in a straight line unless acted upon by an external net force different from zero"
This means that if there are no forces acting on an object, the object stays at rest (if it was not moving previously) or it continues moving with same velocity (if it was already moving) in a straight line.
In this problem, the Earth is initially moving around the Sun, with a certain tangential velocity v. When the Sun disappears, the force of gravity that was keeping the Earth in circular motion disappears too: therefore, there are no more forces acting on the Earth, and so by the 1st law of Newton, the Earth will continue moving with same velocity v in a straight line.
We need the frequency of the photon, it is v = c/ λ
Where c is 3 x 10^8 ms^-1 and λ
is the wave length
We also need the expression of
connecting frequency to energy of photon
which is E = hv where h is Planck’s
constant
Combining the two equations
will give us:
E = h x c/λ
Inserting the values, we will
have:
E = 6.626 x 10^-34 x 3 x 10^8 /
0.126
E = 1.578 x 10^ -24 J
Answer:
P = ρRT/M
Explanation:
Ideal gas equation is given as follows generally:
PV = nRT (1)
P = pressure in the containing vessel
V = volume of the containing vessel
n = number of moles
R = gas constant
T = temperature in K
n = m/M
m = mass of the gas contained in the vessel in g
M = molar mass in g/mol
ρ = m/V
Density of the gas = ρ
Substituting for n in (1)
PV = mRT/M. (2)
Dividing equation (2) through by V
P = m/V ×RT/M
P = ρRT/M
