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svp [43]
2 years ago
12

A client has these arterial blood gas values: anion gap 20 mEq/L (20 mmol/L), pH 7.29, PCO2 37 mm Hg (4.92 mmol/L), HCO3- 11 mEq

/L (11 mmol/L), base excess -6 mEq/L (-6 mmol/L). With what condition do these values correspond?
Chemistry
1 answer:
dangina [55]2 years ago
7 0

Answer:

Since, the client has a low blood pH of 7.29 ( pH less than 7.35) and low bicarbonate 11 mEq/L (less than 22 mEq/L). Therefore, the client is suffering from <u>acidemia due to Metabolic acidosis.</u>

Explanation:

Metabolic acidosis refers to a condition in which the body produces high amounts of acid or the inability of the kidney to remove the excess acid from the body, due to low amount of bicarbonate in the kidney (less than 22 mEq/L). Metabolic acidosis can cause low blood pH ( pH less than 7.35), this condition is known as acidemia.

Therefore, an increase in the generation of acid in the body or low amount of bicarbonate in kidney, can reduce the pH of the blood.

Since, the client has a low blood pH of 7.29 ( pH less than 7.35) and low bicarbonate 11 mEq/L (less than 22 mEq/L).

<u>Therefore, the client is suffering from acidemia due to metabolic acidosis.</u>

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Answer:

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Explanation:

5 0
2 years ago
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Roundup, an herbicide manufactured by Monsanto, has the formula C3H8NO5P. How many moles of molecules are there in a 669.1-g sam
Vedmedyk [2.9K]

Answer:

2.4 ×10^24 molecules of the herbicide.

Explanation:

We must first obtain the molar mass of the compound as follows;

C3H8NO5P= [3(12) + 8(1) + 14 +5(16) +31] = [36 + 8 + 14 + 80 + 31]= 169 gmol-1

We know that one mole of a compound contains the Avogadro's number of molecules.

Hence;

169 g of the herbicide contains 6.02×10^23 molecules

Therefore 669.1 g of the herbicide contains 669.1 × 6.02×10^23/ 169 = 2.4 ×10^24 molecules of the herbicide.

7 0
2 years ago
This is the chemical formula for methyl acetate: CH32CO2. Calculate the mass percent of hydrogen in methyl acetate. Round your a
WITCHER [35]

<u>Answer:</u> The mass percent of hydrogen in methyl acetate is 8 %

<u>Explanation:</u>

The given chemical formula of methyl acetate is CH_3COOCH_3

To calculate the mass percentage of hydrogen in methyl acetate, we use the equation:

\text{Mass percent of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of methyl acetate}}\times 100

Mass of hydrogen = (6 × 1) = 6 g

Mass of methyl acetate = [(3 × 12) + (6 × 1) + (2 × 16)] = 74 g

Putting values in above equation, we get:

\text{Mass percent of hydrogen}=\frac{6g}{74g}\times 100=8.10\%=8\%

Hence, the mass percent of hydrogen in methyl acetate is 8 %

8 0
2 years ago
Paige heated 3.00 g mercury (II) oxide (HgO, 216.59 g/mol) to form mercury (Hg, 200.59 g/mol) and oxygen (O2, 32.00 g/mol). She
stepan [7]

the balanced chemical equation for decomposition of HgO is as follows

2HgO --> 2Hg + O₂

stoichiometry of HgO to O₂ is 2:1

number of HgO moles heated are - 3.00 g / 216.59 g/mol = 0.0139 mol

according to stoichiometry of reaction -

number of O₂ moles formed = 0.0139 mol/ 2 = 0.00695 mol

mass of O₂ to be formed - 0.00695 mol x 32.00 g/mol = 0.2224 g

but the actual yield = 0.195 g

percent yield = actual yield / theoretical yield x 100 %

percent yield = 0.195 g / 0.2224 g x 100 % = 87.7 %

answer is 87.7 %

8 1
2 years ago
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If 0.278g of argon dissolves in 1.5 l of water at 62 bar, what quantity of argon will dissolve at 78 bar
irinina [24]
When P1/P2 = C1/C2

and C is the molarity which = moles/volume

so, P1/P2 = [(mass1/mw)/volume] / [(mass2/mw)/volume]

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                = 0.35 g

∴ the quantity of argon that will dissolve at 78 bar = 0.35 g


5 0
2 years ago
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