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blsea [12.9K]
2 years ago
6

One way to measure temperature in some applications is to monitor the gas pressure in a rigid, closed container. What is the tem

perature of such a vessel, calibrated to read 1.000 atm at STP, if the pressure reads 1.250 atm?
Chemistry
1 answer:
julia-pushkina [17]2 years ago
6 0

Answer:

296.43 K is the temperature of a vessel when pressure reads 1.250 atm.

Explanation:

At STP, when pressure is 1.000 atm the value of temperature is 273,15 K.

If the pressure at temperature T reads as 1.250 atm.

P_1=1.000 atm, T_1=298.15K

P_2=1.250 atm,T_2=?

Applying Gay Lussac's law:

\frac{P_1}{T_1}=\frac{P_2}{T_2} (At constant volume)

\frac{1.000 atm}{273.15 K}=\frac{1.250 atm}{T_2}

T_2=296.43 K

296.43 K is the temperature of a vessel when pressure reads 1.250 atm.

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Ionising radiation is emitted all the time by __________ sources. What one word completes the sentence?
sveticcg [70]

Answer:Radioactive substances give out radiation all of the time. There are three types of nuclear radiation: alpha, beta and gamma. Alpha is the least penetrating, while gamma is the most penetrating. Nonetheless, all three are ionising radiation: they can knock electrons out of atoms and form charged particles.

8 0
2 years ago
Using the van der Waals equation, the pressure in a 22.4 L vessel containing 1.00 mol of neon gas at 100 °C is ________ atm. (a
svetoff [14.1K]

Answer:

The answer to your question is        P = 1.357 atm

Explanation:

Data

Volume = 22.4 L

1 mol

temperature = 100°C

a = 0.211 L² atm

b = 0.0171 L/mol

R = 0.082 atmL/mol°K

Convert temperature to °K

Temperature = 100 + 273

                      = 373°K

Formula

               (P + \frac{a}{v^{2}} )(v - b) = RT

Substitution

               (P + \frac{0.211}{22.4})(22.4 - 0.0171) = (0.082)(373)

Simplify

               (P + 0.0094)(22.3829) = 30.586

Solve for P

                           P + 0.0094 = \frac{30.586}{22.3829}

                           P + 0.0094 = 1.366

                                 P = 1.336 - 0.0094

                                P = 1.357 atm

7 0
2 years ago
The enthalpy change for the explosion of ammonium nitrate with fuel oil is –7198 kJ for every 3 moles of NH4NO3. What is the ent
anastassius [24]

Answer:

−2399.33 kJ

Explanation:

If NH₄NO₃ reacts with fuel oil to give a ΔH of -7198 for every 3 moles of NH₄NO₃

What is the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction

∴ For every 1 mole, we will have \frac{1}{3} of the total enthaply of the 3 moles

so, to determine the 1 mole; we have:

\frac{1}{3}*(-7198kJ)

= −2399.33 kJ

∴ the enthalpy change for 1.0 mole of NH₄NO₃ in this reaction = −2399.33 kJ

7 0
2 years ago
Automobile batteries are filled with an aqueous solution of sulfuric acid. What is the mass of the acid (in grams) in 800. mL of
Grace [21]

Answer:

391.462 g

Explanation:

First, let's calculate the total mass of the solution by the definition of density (d)

d = m/V, where <em>m</em> is the mass in gram and <em>V</em> the volume in mL. So for the given solution

1.285 = m/800

m = 1028 g

The mass of sulfuric acid will be:

0.3808x1028 = 391.462 g

7 0
2 years ago
A patient needs to be given exactly 500 ml of a 5.0% (w/v) intravenous glucose solution. the stock solution is 35% (w/v). how ma
N76 [4]
In this question, the <span>patient needs to be given exactly 500 ml of a 5.0%. The content of the glucose should be:
</span>weight= volume * density* concentration<span>
500ml * 1mg/ml *5%= 25mg.

The </span><span>stock solution is 35%, then the amount needed in ml would be: 
weight= volume * density* concentration
25mg= volume * 1mg/ml *35%
volume= 25/35%= 500/7= 71.43ml</span>
6 0
2 years ago
Read 2 more answers
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