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marusya05 [52]
2 years ago
5

The tire above has a recommended tire pressure of 35 PSI, however, its current pressure is only 26 PSI. Which of the following c

ould occur if driven on? (A) A tire blowout. (B) Unstable handling of the vehicle. (C) Both A & B.
Physics
1 answer:
Dima020 [189]2 years ago
7 0

Answer:

option B  

Explanation:

It is given that in the tire the recommended pressure is 35 PSI however the current pressure is only 26 PSI which means that pressure in the tire is less than the recommended so the chances of blowout of the tire gets eliminated hence option A is not correct.

Having pressure less in the tire can lead to the Unstable handling of the vehicle.

so correct answer is option B  

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The heaviest wild lion ever measured had a mass of 313 kg. Suppose this lion is walking by a lake when it sees an empty boat flo
11Alexandr11 [23.1K]

Answer:

The kinetic energy dissipated is 3286.5 J

Explanation:

K.E before collision = 1/2m1v1^2 = 1/2×313×6^2 = 5634 J

K.E after collision = 1/2(m1+m2)v2^2

From the law of conservation of momentum:

m1+m2 = m1v1/v2 = 313×6/2.5 = 751.2 kg

K.E after collision = 1/2×751.2×2.5^2 = 2347.5 J

K.E dissipated = 5634 J - 2347.5 J = 3286.5 J

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2 years ago
A student throws a 0.22 kg rock horizontally at 20.0 m/s from 10.0 m above the ground. Find the initial kinetic energy of the ro
LekaFEV [45]

Answer:

44J

Explanation:

Given parameters:

Mass of rock  = 0.22kg

Initial velocity  = 20m/s

Distance moved  = 10m

Unknown:

Initial kinetic energy of the rock  = ?

Solution:

To solve this problem, we need to understand that kinetic energy is the energy due to the motion of a body.

It is mathematically expressed as;

     Kinetic energy  = \frac{1}{2} m v²

m is the mass

v is the velocity

   Kinetic energy  =  \frac{1}{2} x 0.22 x 20²   = 44J

6 0
1 year ago
Stu wanted to calculate the resistance of a light bulb connected to a 4.0 V battery, with a resulting current of 0.5 A. He used
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His answer was incorrect because according to ohm's law the formula used should have been R=V/I instead of multiplying and the answer should be 8ohms
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A wooden disk of mass m and radius r has a string of negligible mass is wrapped around it. If the disk is allowed to fall and th
Tju [1.3M]

Answer:

a = \frac{2}{3}g

T = \frac{mg}{3}

Explanation:

As the disc is unrolling from the thread then at any moment of the time

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mg - T = ma

also by torque equation we can say

TR = I\alpha

TR = \frac{1}{2}mR^2(\frac{a}{R})

T = \frac{1}{2}ma

Now we have

mg - \frac{1}{2}ma = ma

mg = \frac{3}{2}ma

a = \frac{2}{3}g

Also from above equation the tension force in the string is

T = \frac{1}{2}ma

T = \frac{mg}{3}

7 0
2 years ago
A rectangular conducting loop of wire is approximately half-way into a magnetic field B (out of the page) and is free to move. S
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Answer:

. The loop is pushed to the right, away from the magnetic field

Explanation

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