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aleksandr82 [10.1K]
2 years ago
4

The image of a plant is 4.0 cm from a concave spherical mirror having a radius of curvature of 10 cm. Where is the plant relativ

e to the mirror?
Physics
1 answer:
Art [367]2 years ago
5 0

Answer:

The plant is placed at 2.22 cm on left hand side of the mirror.

Explanation:

Distance of the object from the mirror = u

Distance of an image from the mirror = v = 4.0 cm

Radius of the Curvature of the mirror ,r= 10 cm

f=\frac{-r}{2}

f=\frac{-10 cm}{2}= -5 cm

1 ) v = +4.0 cm (Image is on the other side)

\frac{1}{-5 cm}=\frac{1}{u}+\frac{1}{4.0 cm}

u = -2.22 cm

2) v = -4.0 cm (Image is on the same side)

\frac{1}{-5 cm}=\frac{1}{u}+\frac{1}{-4.0 cm}

u = 20 cm (not possible)

So, the distance of plant from the mirror is 2.22 cm

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Suppose a 500 mb chart valid today at 12 Z indicates a large trough over the eastern US and a large ridge over the western US. A
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A puck of mass m = 0.085 kg is moving in a circle on a horizontal frictionless surface. It is held in its path by a massless str
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Answer:

T = 11.93 N

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Newton's second law to the puck in the circular path

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in  radial direccion (N)

m : puck mass  (kg)

a : radial acceleration of the puck (m/s²)

Data:

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t= 0.45 s

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a = (13.96) ²* (0.72)

a = 140.3 m/s²

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4 0
2 years ago
Ron fills a beaker with glycerin (n = 1.473) to a depth of 5.0 cm. if he looks straight down through the glycerin surface, he wi
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7 0
2 years ago
A source charge generates an electric field of 1236 N/C at a distance of 4 m. What is the magnitude of the source charge?
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The correct answer to the question is-  2.2\ \mu C

CALCULATION:

As per the question, the electric field generated by the source charge is 1236  N/C at a distance of 4 m.

Hence , electric field  E =  1236 N/C.

The distance of the point R = 4m

We are asked to calculate the charge possessed by the source.

The electric field produced by a source charge of Q at a distance R is calculated as -

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Hence, the charge of source is calculated as -

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Hence, the charge of source is 2.2\ \mu C

3 0
2 years ago
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