Question

When a downward force is applied at a point 0.60 m to the left of a fulcrum, equilibrium is obtained by placing a mass of 10–7 kg at a point 0.40 m to the right of the fulcrum. What is the magnitude of the downward force

Answer 1

Answer:

force = 6.53×  $10^{-7}$ N

Explanation:

Given data

downward force = 0.60 m

mass m  = $10^{-7}$ kg

distance h = 0.40 m

to find out

magnitude of the downward force

solution

we know here mg is apply 0.4 m away from support and

so applied force is d =  0.6 m from support

so

by balancing torque we can calculate force

that is

force = mass  × g ×  h / d

put here all these value

force =  mass  × g ×  h / d

force =  ( $10^{-7}$  × 9.81 ×  0.4 )  / 0.6

force = 6.53×  $10^{-7}$ N