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miv72 [106K]
2 years ago
15

The signal to a speaker causes .5 amps of current. The signal level is increased to 2.5 amps. What is the gain, rounded to the n

earest decibel?
Physics
1 answer:
devlian [24]2 years ago
7 0

Explanation:

It is given that,

The signal to a speaker causes 0.5 amps of current, I_1=0.5\ A

The signal level is increased to 2.5 amps, I_2=2.5\ A

We need to find the gain to the nearest decibel. The decibel gain formula of the speaker is given by :

db=20\ log(\dfrac{I_2}{I_1})

db=20\ log(\dfrac{2.5}{0.5})

db = 13.97 db

or

db = 14 db

So, the gain pf the speaker is 14 db. Hence, this is the required solution.

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You have negotiated with the Omicronians for a base on the planet Omicron Persei 7. The architects working with you to plan the
steposvetlana [31]

Answer:

5.724 meters / second^2

Explanation:

We are given two pieces of information, 5.24 flurg = 1 meter, 1 grom = 0.493 second. If that is so, we can say that there are two possible conversion units,  5.25 flurg / meter, and 0.493 second / grom.

_____

We want to convert 7.29 flurg / grom^2 ( I believe? ) to the units meters / second^2. But, let's break this down into bits. It would be convenient to first convert 7.29 flurg / grom^2 to the units meters / grom^2, by dividing the conversion factors as to cancel out the appropriate things, which we will go into detail on a bit later ( using the first conversion factor ). Respectively we can convert meters / grom^2 to meters / grom * s, canceling out the flurg ( through the second conversion factor ). And now we would need to get rid of the grom, dividing similarly.

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( 1 ) ( flurg / grom^2 ) / ( flurg / meters  ) - first conversion unit

= flurg / grom^2 * meters /flurg

= ( meters * flurg ) / ( grom^2 * flurg )  

= meters /grom^2,

7.29 flurg / grom^2 / 5.24 flurg / meter = ( About ) 1.39 meter / grom^2

( 2 ) ( meter / grom^2 ) / ( second / grom  ) - second conversion unit

= meter / grom^2 * grom / second

= ( meter * grom ) / ( grom^2 * second )

= meter / ( grom * second ),

( 1.39 meter / grom^2 ) / 0.493 second / grom = ( About ) 2.82195 meter /  grom * second

( 3 ) ( 2.82195 meter / ( grom * second ) ) / 0.493 second / grom = 5.724 meter / second^2

( And thus, the value of gOP7 in the units the architects will use should be about 5.724 meters / second^2 )

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2 years ago
1. A car is 140 kg, and drove East 13.5 m/s. Car B is 157 kg and drove West at 10.9 m/s.
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The velocity would switch on the cars
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Heat is allowed to flow from the heat source of a heat engine at 425 K to a cold sink at 313 K. What is the efficiency of the he
olga2289 [7]
I assume here that the engine operates following a Carnot cycle, which achieves the maximum possible efficiency. 

Under this assumption, the efficiency of the engine (so, the efficiency of the Carnot cycle) is given by
\eta = 1- \frac{T_{cold}}{T_{hot}}
where
T_{cold} is the cold temperature
T_{hot} is the hot temperature

For the engine in our problem, the cold temperature is 313 K while the hot temperature is 425 K, so the effiency of the engine is
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3 0
2 years ago
Read 2 more answers
A solenoid with 3,000.0 turns is 70.0 cm long. If its self-inductance is 25.0 mH, what is its radius? (The value of μ0 is 4π x 1
nevsk [136]

Answer:

A. 2.2*10^-2m

Explanation:

Using

Area = length x L/ uo xN²

So A = 0.7m * 25 x 10^-3H /( 4π x10^-7*

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A = 17.5*10^-3/ 1.13*10^-5

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Explanation:

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2 years ago
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Explanation :

It is given that,

BMR i.e basal metabolic rate is 88 kcal/hr. So, BMR in watts is converted by the following :

We know that, 1 kilocalorie = 4184 joules

So, 1\ kcal/h=\dfrac{1\times 4184\ J}{3600\ sec}

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So, it can be seen that the body can accommodate a modes amount of activity in hot weather but strenuous activity would increase the metabolic rate above the body's ability to remove heat.

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