Answer:
The value is 
Explanation:
Generally the velocity attained by the sled after t = 3.10 s is mathematically evaluated using the kinematic equation as follows

Here u = 0 \ m/s
a = 13.5 
So
=>
The is distance it covers at this time is

=> 
=> 
Now when sled stops its the final velocity is
while the initial velocity will be the velocity after its acceleration i.e
So

Here
, the negative sign shows that it is deceleration
So

=> 
Answer:
F = Gm1m2/r^2 where G = 6.67x10^-11, m1 =1300, m2 = 7800, r = 0.23m
F = 6.67x10^-11 *1300*7800/(0.23)^2 = 0.0127852N
Explanation:
Answer:
16,18,22
Or
1,3,7
Explanation:
The detailed explanation is contained in the image attached. The lengths are found using Pythagoras theorem and the two lengths reflects the two values of x yielded by the quadratic equation
Answer:
a) f = 615.2 Hz b) f = 307.6 Hz
Explanation:
The speed in a wave on a string is
v = √ T / μ
also the speed a wave must meet the relationship
v = λ f
Let's use these expressions in our problem, for the initial conditions
v = √ T₀ /μ
√ (T₀/ μ) = λ₀ f₀
now it indicates that the tension is doubled
T = 2T₀
√ (T /μ) = λ f
√( 2To /μ) = λ f
√2 √ T₀ /μ = λ f
we substitute
√2 (λ₀ f₀) = λ f
if we suppose that in both cases the string is in the same fundamental harmonic, this means that the wavelength only depends on the length of the string, which does not change
λ₀ = λ
f = f₀ √2
f = 435 √ 2
f = 615.2 Hz
b) The tension is cut in half
T = T₀ / 2
√ (T₀ / 2muy) = f = λ f
√ (T₀ / μ) 1 /√2 = λ f
fo / √2 = f
f = 435 / √2
f = 307.6 Hz
Traslate
La velocidad en una onda en una cuerda es
v = √ T/μ
ademas la velocidad una onda debe cumplir la relación
v= λ f
Usemos estas expresión en nuestro problema, para las condiciones iniciales
v= √ To/μ
√ ( T₀/μ) = λ₀ f₀
ahora nos indica que la tensión se duplica
T = 2T₀
√ ( T/μ) = λf
√ ) 2T₀/μ = λ f
√ 2 √ T₀/μ = λ f
substituimos
√2 ( λ₀ f₀) = λ f
si suponemos que en los dos caso la cuerda este en el mismo armónico fundamental, esto es que la longitud de onda unicamente depende de la longitud de la cuerda, la cual no cambia
λ₀ = λ
f = f₀ √2
f = 435 √2
f = 615,2 Hz
b) La tension se reduce a la mitad
T = T₀/2
RA ( T₀/2μ) = λ f
Ra(T₀/μ) 1/ra 2 = λ f
fo /√ 2 = f
f = 435/√2
f = 307,6 Hz
Answer:
295.42 N
Explanation:
From Newton's law of universal gravitation.
F = Gmm'/r².................. Equation 1
Where F = Gravitational force, G = Universal constant, m = mass of the human, m' = mass of mass, r = radius of mass.
Given: m = 80 kg, m' = 6.4×10²³ kg, r = 3.4×10⁶ m.
Constant: G = 6.67×10⁻¹¹ Nm²/Kg²
Substitute into equation 1
F = 6.67×10⁻¹¹(80)(6.4×10²³ )/( 3.4×10⁶)²
F = 3415.04×10¹²/(11.56×10¹²)
F = 3415.04/11.56
F = 295.42 N
Hence the gravitational force = 295.42 N