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Levart [38]
2 years ago
11

Two cars collide head-on on a level friction-free road. The collision was completely inelastic and both cars quickly came to res

t during the collision. What is true about the velocity of this system's center of mass? Select one: a. It was never zero. b. It was always zero. c. It was not zero, but ended up zero. d. None of the above.
Physics
1 answer:
tangare [24]2 years ago
3 0

Answer:

b. It was always zero

Explanation:

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The length of a wooden rod is 25.5 cm. What is this length in:<br>(a) millimetres?<br>(b) metres?​
larisa86 [58]

Answer:

(a)255mm \\ (b)0.255m

Explanation:

(a)1cm = 10mm \\ 25.5cm = x

Cross multiply

1x = 25.5 \times 10 \\ x = 255mm

(b)100cm = 1m \\ 25.5cm = x

cross multiply

100x = 25.5 \\  \frac{100x}{100}  =  \frac{25.5}{100}  \\ x = 0.255m

hope this helps

brainliest appreciated

good luck! have a nice day!

4 0
2 years ago
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HELP PLSSSSSSS ASAP FIRST CORRECT ANSWER WILL GET BRANLIST. A bunny accidentally knocks a basket of eggs off of a table. Luckily
mezya [45]

Answer:

A

Explanation:

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8 0
2 years ago
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if a net horizontal force of 175 N is applied to a bike whos mass is 43 kg what acceleration is produced
Anna [14]

Explanation:

f=175N

m=43kg

a=?

know

f=ma

a=f/m

a=175/43

a=4.06m/s

3 0
2 years ago
Two blocks, 1 and 2, are connected by a rope R1 of negligible mass. A second rope R2, also of negligible mass, is tied to block
alekssr [168]

Answer:

Explanation:

Given

Two block are connected by rope R_1

R_2 rope is attached to block 2

suppose F_2 is a force applied to Rope R_2

Applied force F_2=Tension in Rope 2

F_2=(m_1+m_2)a---1

where a=acceleration of system

Tension in rope R_1 is denoted by F_1

F_1=m_1a---2

divide 1 and 2 we get

\frac{F_2}{F_1}=\frac{(m_1+m_2)a}{m_1a}

also m_1=2.11\cdot m_2

\frac{F_2}{F_1}=\frac{2.11m_2+m_2}{2.11m_2}

\frac{F_2}{F_1}=\frac{3.11}{2.11}

\frac{F_1}{F_2}=\frac{2.11}{3.11}

               

3 0
2 years ago
Suppose an isolated box of volume 2V is divided into two equal compartments. An ideal gas occupies half of the container and the
SpyIntel [72]

Answer:

A. the internal energy stays the same

Explanation:

From the first law of thermodynamics, "energy can neither be created nor destroyed but can be transformed from one form to another.

Based on this first law of thermodynamic, the new internal energy of the gas is the same as the internal energy of the original system.

Therefore, when the partition separating the two halves of the box is removed and the system reaches equilibrium again, the internal energy stays the same.

7 0
2 years ago
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