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kogti [31]
2 years ago
4

A horizontal clothesline is tied between 2 poles, 14 meters apart. When a mass of 4 kilograms is tied to the middle of the cloth

esline, it sags a distance of 3 meters.What is the magnitude of the tension on the ends of the clothesline?Tension =

Physics
1 answer:
Rus_ich [418]2 years ago
7 0

Answer:

The magnitude of the tension on the ends of the clothesline is 21.32 N.

Explanation:

Given that,

Distance = 14 m

Mass = 4 kg

Height = 3 m

We need to calculate the angle made with vertical mass

\theta=\tan^{-1}\dfrac{7}{3}

\theta=66.80^{\circ}

We need to calculate the magnitude of the tension on the ends of the clothesline

Using formula of tension

2T\sin\theta-mg=0

Put the value into the formula

T=\dfrac{4\times9.8}{2\sin66.80}

T=21.32\ N

Hence, The magnitude of the tension on the ends of the clothesline is 21.32 N.

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Answer:600 miles, 12

Explanation: The movement described in the question exhibits that of a polygon. Exhibiting a constant distance and angle with only varying direction until the starting point is reached.

The sum of exterior angles of a polygon = 360 degrees.

Exterior angle of a polygon = (360 ÷ number of sides)

Therefore,

Number of sides = 360 ÷ exterior angle

Exterior angle = 30 degrees

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Since distance traveled of 50 miles is the same for each displacement ;

Total displacement = distance traveled * number of sides

Total displacement = 50 * 12 = 600 miles.

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The answer is the second one of it that
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hockey puck slides across the ice with an initial velocity of 7.2 m/s. It has a deceleration of 1.1 m/s2 and is traveling toward
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For this use the formula:

d = Vo * t - (at^2) / 2

Clearing t:

t = d/(v + 0.5*a)

Replacing:

t = 5 m / (7.2 m/s + 0.5 * (-1.1 m/s²)

Resolving:

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Step 1:

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