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djverab [1.8K]
2 years ago
14

Show that if A CB, then A = B ( B A ). Show that if A C B, then A U (B \ A) = B. Show, by example, that for sets A, B, and C, AN

B = An C does not imply B = C.
Mathematics
1 answer:
Shtirlitz [24]2 years ago
8 0

Answer: If A ⊂ B, then A = B \ ( B \ A)

ok, when you do B \ A, you are subtracting all the elements in A∩B from B. So the only elements remaining are those who aren't in A.

If we subtract this of B again, we are subtracting of B all the elements that aren't in A, so the only elements remaining are those who belongs in A.

If A ⊂ B then A U (B \ A) = B.

Again, when you do B \ A you are extracting all the elements that belongs to the A∩B from B. So you are extracting al the elements from A. and when you add all the elements of A again, then you recuperate B.

if AnC = AnC does not imply that B = C.

if A = {1,2}, B = {1,2,3,4,5} and C = {1,2,3}

then AnC = {1,2} and AnB = {1,2} but B and C are different.

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A manager states that his process is really working well. Out of 1,500 parts, 1,477 were produced free of a particular defect an
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Answer:

The answer is explained below

Step-by-step explanation:

STEP 1

Out of 1500 units produced by a company 1,477 are found to be free of a particular type of defect. One needs to rate the performance based on Six Sigma Theory.

STEP 2

Manager can define the performance of a product using defects per million units DPMO metric

DPMO can be find by using

DPMO = Total number of defects in a sample/ No. of opportunities of per error per unit x No. of units * 1,000,000

          = 1500 - 1477/ 1 x 1500* 1,000,000

          = 23/1500

          = 15,333,33

The defect rate of the process can be find by

Defect rate = No. of defects/ No. of units * 100

                   = 1500 - 1477/1500 * 100

                   = 23/1500 * 100

                   = 1.53%

Six Sigma theory focuses on achieving 3.4 defects per million for a certain period of time. However in this, performance of the process is not as good as stated by the manager.

8 0
2 years ago
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Let $f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5$. Without using long division (which would be horribly nasty!), find the remainder when
valentina_108 [34]

Solution:

f(x) = x^{10}-8x^8-8x^3+12x^2-5x-5

We have to find the remainder when f(x) is divided by x^2-1.

x²-1=0

x=\pm1

f(1)=1^{10}-8(1)^8-8(1)^3+12(1)^2-5(1)-5=1-8-8+12-5-5=1-16+12-10=13-26=-13\\\\f(-1)=(-1)^{10}-8(-1)^8-8(-1)^3+12(-1)^2-5(-1)-5=1-8+8+12+5-5=1+12=13

So, remainder is 13 and -13.

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2 years ago
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Please Please Help Ne In This Math homework?!?!?!
weeeeeb [17]
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2 years ago
What three different equations that have x = 5 as a solution
Mars2501 [29]
5x=25 could be one.
25/x-3=2 is another.
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2 years ago
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Parallelogram ABCD is rotated to create image A'B'C'D'. On a coordinate plane, 2 parallelograms are shown. The first parallelogr
Gala2k [10]

Answer:

(x,y)→(y,-x)

Step-by-step explanation:

Parallelogram ABCD:

A(2,5)

B(5,4)

C(5,2)

D(2,3)

Parallelogram A'B'C'D':

A'(5,-4)

B'(4,-5)

C'(2,-5)

D'(3,-2)

Rule:

A(2,5)→A'(5,-2)

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C(5,2)→C'(2,-5)

D(2,3)→D'(3,-2)

so the rule is

(x,y)→(y,-x)

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2 years ago
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