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madam [21]
2 years ago
15

Consider a U-tube whose arms are open to the atmosphere. Now water is poured into the U-tube from one arm, and light oil (???? =

790 kg/m3) from the other. One arm contains 70-cm-high water, while the other arm contains both fluids with an oil-to-water height ratio of 6. Determine the height of each fluid in that arm.

Chemistry
1 answer:
IgorC [24]2 years ago
8 0

Answer:

Oil high= 73.14cm

Water high= 12.19cm

Explanation:

See the attached images.

The first important concept is that in an open tube at both ends the atmospheric pressure balances itself.

The pressure on both sides of the tube is the same in the equilibrium. The pressure of each fluid depends on its height and density.

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Suppose you are studying the K sp of K C l O 3 , which has a molar mass of 122.5 g/mol, at multiple temperatures. You dissolve 4
Ghella [55]

Answer:

The K sp Value is  K_{sp}=7.40

Explanation:

From the question we are told that

   The of KClO_3 is = 122.5 g/ mol

    The mass of KClO_3 dissolved is m_s = 4.0g

    The volume of solution is  V_s = 12mL = 12*10^{-3}L

The number of moles of KClO_3 is mathematically evaluated as

           No \ of  \ moles  \ = \frac{mass }{Molar \ mass}

Substituting values

                                  = \frac{4}{122.5}

                                  =0.0327\ moles

Generally concentration is mathematically represented as

         concentration = \frac{No \ of \ moles}{volume }

For KClO_3        

               Z= \frac{0.0327}{12*10^{-3}}

                              =2.72 \ mol/L

The dissociation reaction of KClO_3  is

         KClO_3 \ ----> K^{+}_{(aq)} + ClO_3^-_{(aq)}

The solubility product constant is mathematically represented as

                   K_{sp} = \frac{concentration of ionic product }{concentration of ionic reactant }

Since there is no ionic reactant we have

                  K_{sp} = [k^+] [ClO_3^-]

                          = Z^2

                          = 2.72^2

                          K_{sp}=7.40

                         

5 0
2 years ago
Read 2 more answers
A scientist measures the mass of two liquids before and after combining them. The mass after combining the liquids is less then
Lelu [443]

Answer:

A chemical change occurred and a gas was produced.  

Step-by-step explanation:

If there is no chemical reaction, the <em>Law of Conservation of Mass</em> says that  

Total mass = Mass 1 + Mass 2

However, if the two liquids react and give off a gas, then

Total mass = Mass 1 + Mass 2 + Mass of gas

You are not measuring the mass of the gas, so the mass of the liquids after mixing is less than it was before mixing.

For example, if Liquid 1 was a solution of HCl and Liquid 2 was a solution of Na₂CO₃, they would give off CO₂ on mixing. but you would not be measuring the mass of the CO₂.

4 0
2 years ago
A running track measures 1056 ft per lap. To run 15.0 km, how many laps should you run?
Neporo4naja [7]

Answer:

46.6 laps

Explanation:

Step 1: Given data

  • Length of the lap (l): 1056 ft
  • Total distance to be run (d): 15.0 km

Step 2: Convert "l" to km

We will use the conversion factor 1 km = 3280.84 ft.

1056 ft × (1 km / 3280.84 ft) = 0.3219 km

Step 3: Calculate the number of laps that you should run

We will use the following expression.

laps = d/l

laps = 15.0 km/(0.3219 km/lap)

laps = 46.6 laps

7 0
2 years ago
The ΔG°f of atomic oxygen is 230.1 kJ/mol. Find ΔG° for the following dissociation reactionO2 (g) &lt;--&gt; 2O (g)then calculat
marusya05 [52]

Answer:

Kc = 2.145 × 10⁻⁸¹

Explanation:

Let's consider the following reaction:

O₂(g) ⇄ 2O(g)

The standard Gibbs free energy for the reaction (ΔG°) can be calculated using the following expression:

ΔG° = Σnp. ΔG°f(p) - Σnp. ΔG°f(p)

where,

ni are the moles of products and reactants

ΔG°f(p) are the standard Gibbs free energy of formation of products and reactants

In this case,

ΔG° = 2 × ΔG°f(O) - 1 × ΔG°f(O₂)

ΔG° = 2 × 230.1 kJ/mol - 1 × 0 kJ/mol

ΔG° = 460.2 kJ/mol

With this information, we can calculate the equilibrium constant (Kc) using the following expression:

Kc=e^{-\Delta G \°/R.T } = e^{-460.2 kJ/mol/(8.314 \times 10^{-3}kJ/mol.K)  \times 298K }=2.145 \times 10^{-81}

3 0
2 years ago
An aspirin tablet contains 325.0 mg of aspirin, which has the molecular formula, C9H8O4. How many molecules of aspirin are in th
Inga [223]

Answer:

1.08X10²¹ molecules aspirin are in the tablet

Explanation:

Molar mass of aspirin is 180.15 g/m (C₉H₈O₄)

This data means that 1 mol weighs 180.15 g so:

325 mg = 0.325 g

If 180.15 g are contained in 1 mol of aspirin

0.325 g (which is the weight from the tablet) are contained in ...

(0.325 g  .1m)/180.15 g = 1.80x10⁻³ moles

1 mol has 6.02x10²³ molecules (NA)

1.80x10⁻³ moles are contained by ...

1.80x10⁻³ . NA = 1.08X10²¹ molecules

6 0
2 years ago
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