Question

O raza de lumina cade sub un unghi de incidenta de 30 de grade pe o suprafata plana ce separa doua materiale transparente cu indicii de refractie 1,60 si 1,40.
Calculati unghiul de refractie (din mediul cu indicele de refractie mai mic)

Answer 1

Answer: $34.84\°$

Explanation:

The question in english is:

A ray of light falls under an angle of incidence of 30 degrees on a flat surface that separates two transparent materials with index of refractions 1.60 and 1.40, respectively.

Calculate the angle of refraction (from the environment with the lower index of refraction)

According to Snell’s Law:  

$n_{1}sin(\theta_{1})=n_{2}sin(\theta_{2})$ (1)  

Where:  

$n_{1}=1.6$ is the first medium index  of refraction

$n_{2}=1.4$ is the second medium index  of refraction

$\theta_{1}=30\°$ is the angle of the incident ray  

$\theta_{2}$ is the angle of the refracted ray

We need to find $\theta_{2}$ from (1):

$\theta_{2}=sin^{-1}(\frac{n_{1}}{n_{2}}sin\theta_{1}$ (2)  

$\theta_{2}=sin^{-1}(\frac{1.6}{1.4}sin(30\°)$ (3)

Finally:

$\theta_{2}=34.84\°$