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Zarrin [17]
2 years ago
13

This problem explores the behavior of charge on conductors. We take as an example a long conducting rod suspended by insulating

strings. Assume that the rod is initially electrically neutral. For convenience we will refer to the left end of the rod as end A, and the right end of the rod as end B. In the answer options for this problem, "strongly attracted/repelled" means "attracted/repelled with a force of magnitude similar to that which would exist between two charged balls.A small metal ball is given a negative charge, then brought near (i.e., within about 1/10 the length of the rod) to end A of the rod. What happens to end A of the rod when the ball approaches it closely this first time?
Physics
1 answer:
Olegator [25]2 years ago
3 0

Answer:

rod end A is strongly attracted towards the balls

rod end B is weakly repelled by the ball as it is at a greater distance

Explanation:

When the ball with a negative charge approaches the A end of the neutral bar, the charge of the same sign will repel and as they move they move to the left end, leaving the rod with a positive charge at the A end and a negative charge of equal value at end B.

Therefore rod end A is strongly attracted towards the balls and

rod end B is weakly repelled by the ball as it is at a greater distance

You might be interested in
A professor's office door is 0.99 m wide, 2.2 m high, 4.2 cm thick; has a mass of 27 kg, and pivots on frictionless hinges. A "d
ANEK [815]

Answer:

I=8.8209\ kg.m^2

\alpha=0.6348\ rad.s^{-2}

Explanation:

Given:

  • width of door, w=0.99\ m
  • height of the door, h=2.2\ m
  • thickness of the door, t=4.2\ cm
  • mass of the door, m=27\ kg
  • torque on the door, \tau=5.6\ N.m

<em>∵Since the thickness of the door is very less as compared to its other dimensions, therefore we treat it as a rectangular sheet.</em>

  • For a rectangular sheet we have the mass moment of inertia inertia as:

I=\frac{1}{3} m.w^2

I=\frac{1}{3}\times 27\times 0.99^2

I=8.8209\ kg.m^2

We have a relation between mass moment of inertia, torque and angular acceleration as:

\alpha=\frac{\tau}{I}

\alpha=\frac{5.6}{8.8209}

\alpha=0.6348\ rad.s^{-2}

6 0
2 years ago
Inna Hurry is traveling at 6.8 m/s, when she realizes she is late for an appointment. She accelerates at 4.5 m/s^2 for 3.2 s. Wh
Alborosie

Answer:

1) v = 21.2 m/s

2) S = 63.33 m

3) s = 61.257 m

4) Deceleration, a = -4.32 m/s²

Explanation:

1) Given,

The initial velocity of Inna, u = 6.8 m/s

The acceleration of Inna, a = 4.5 m/s²

The time of travel, t = 3.2 s

Using the first equation of motion, the final velocity is

                v = u + at

                   = 6.8 + 4.5 x 3.2

                   = 21.2 m/s

The final velocity of Inna is, v = 21.2 m/s

2) Given,

The initial velocity of Lisa, u = 12 m/s

The final velocity of Lisa, v = 26 m/s

The acceleration of Lisa, a = 4.2 m/s²

Using the III equations of motion, the displacement is

                          v² = u² +2aS

                         S = (v² - u²) / 2a

                            = (26² -12²) / 2 x 4.2

                            = 63.33 m

The distance Lisa traveled, S = 63.33 m

3) Given,

The initial velocity of Ed, u = 38.2 m/s

The deceleration of Ed, d = - 8.6 m/s²

The time of travel, t = 2.1 s

Using the II equations of motion, the displacement is

                        s = ut + 1/2 at²

                           =38.2 x 2.1 + 0.5 x(-8.6) x 2.1²

                           = 61.257 m

Therefore, the distance traveled by Ed, s = 61.257 m

4) Given,

The initial velocity of the car, u = 24.2 m/s

The final velocity of the car, v = 11.9 m/s

The time taken by the car is, t = 2.85 s

Using the first equations of motion,

                         v = u + at

∴                        a = (v - u) / t

                            = (11.9 - 24.2) / 2.85

                            = -4.32 m/s²

Hence, the deceleration of the car, a = = -4.32 m/s²

5 0
2 years ago
Read 2 more answers
A certain factory whistle can be heard up to a distance of 2.5 km. Assuming that the acoustic output of the whistle is uniform i
enyata [817]

Answer:

Emitted power will be equal to 7.85\times 10^{-5}watt

Explanation:

It is given factory whistle can be heard up to a distance of R=2.5 km = 2500 m

Threshold of human hearing I=10^{-12}W/m^2

We have to find the emitted power

Emitted power is equal to P=I\times A

P=I\times 4\pi R^2

P=10^{-12}\times 4\times 3.14\times  2500^2=7.85\times 10^{-5}watt

So emitted power will be equal to 7.85\times 10^{-5}watt

4 0
2 years ago
Which optical device can focus light to a point through reflection?
nekit [7.7K]

Answer:

It is A

Explanation:

6 0
2 years ago
Nerve impulses are carried along axons, the elongated fibers that transmit neural signals. We can model an axon as a tube with a
jeka94

Answer:

The resistance of the axon is 1.27\times 10^7\ \Omega.

Explanation:

Given that,

Inner diameter of the model of an axon, d=10\ \mu m

Radius of the model, r=5\ \mu m=5\times 10^{-6}\ m

Resistivity of the fluid inside the tube wall, \rho=0.5\ \Omega -m

Length of the axon, l = 2 mm = 0.002 m

We know that the resistance in terms of resistivity of an object is given by :

R=\rho\dfrac{l}{A}\\\\R=0.5\times \dfrac{0.002}{\pi (5\times 10^{-6})^2}\\\\R=1.27\times 10^7\ \Omega

So, the resistance of the axon is 1.27\times 10^7\ \Omega. Hence, this is the required solution.

8 0
2 years ago
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