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Nady [450]
2 years ago
12

A length of glass tubing is 0.525 m. How many inches long is the tubing? (2.54 cm = 1 inch)

Chemistry
2 answers:
lara31 [8.8K]2 years ago
6 0
If, (.525m)(100 cm/m)(1/2.54 in/cm) = 20.7 in  or C
valkas [14]2 years ago
5 0

Answer : The correct option is, (C) 20.7 inches

Explanation :

The conversion used from meter to centimeter is:

1 m = 100 cm

The conversion used from centimeter to inches is:

2.54 cm = 1 inch

First we have to convert the length of glass tubing from meter to centimeter.

As, 1m=100cm

So, 0.525m=\frac{0.525m}{1m}\times 100cm=52.5cm

Now we have to convert the length of glass tubing from centimeter to inches.

As, 2.54cm=1\text{ inch}

So, 52.5cm=\frac{52.5cm}{2.54cm}\times 1\text{ inch}=20.7\text{ inches}

Therefore, the length of glass tubing in inches are 20.7 inches.

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Upon heating with acid salicylic acid can form a polymer. what is its structure likely to be
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Take a look at the attached picture. This is not the reaction of polymerization of salicylic acid. It just shows the structure of salicylic acid and the structure when it's polymerized. The polymerization is done by connecting the salicylic acids where you produce one molecule of water.

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The following reaction shows sodium hydroxide reacting with sulfuric acid.
amm1812

its answer is 35.5 grams

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What is the poh of an aqueous solution at 25.0 °c that contains 1.35 × 10-8 m hydroxide ion?
ohaa [14]
POH is defined as the negative log base ten of the concentration of base. You have the concentration.
8 0
2 years ago
A molecule of ethyl alcohol is converted to acetaldehyde in one’s body by zero order kinetics. If the concentration of alcohol i
Oliga [24]

Answer:

(1) 0.0016 mol/L

Explanation:

Let the concentration of alcohol after 3.5 hours be y M

The reaction follows a first-order

Rate = ky^0 = change in concentration/time

k = 6.4×10^-5 mol/L.min

Initial concentration = 0.015 M

Concentration after 3.5 hours = y M

Time = 3.5 hours = 3.5×60 = 210 min

6.4×10^-5y^0 = 0.015-y/210

y^0 = 1

0.015-y = 6.4×10^-5 × 210

0.015-y = 0.01344

y = 0.015 - 0.01344 = 0.00156 = 0.0016 mol/L (to 4 decimal places)

5 0
2 years ago
How many moles of CaC2 are needed to react completely with 45.0g H2O?
sertanlavr [38]

Answer:

In order to react with 45 g of water 1.25 moles of CaC₂ are required.

Explanation:

Given data:

Moles of CaC₂ needed = ?

Mass of water = 45.0 g

Solution:

Chemical equation:

CaC₂ + 2H₂O      →      C₂H₂ + Ca(OH)₂

Number of moles of water:

Number of moles = mass/ molar mass

Number of moles = 45 g/ 18 g/mol

Number of moles = 2.5 mol

Now we will compare the moles of water and CaC₂ from balance chemical equation:

                     H₂O             :             CaC₂

                       2                :                1

                     2.5              :             1/2×2.5 =1.25 mol

In order to react with 45 g of water 1.25 moles of CaC₂ are required.

6 0
2 years ago
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