he speed of the student relative to shore is
v_ up = v- vs
v _down = v+ vs
The time required to travel distance d upstream
is
t_up = d/ v_up = d/ v- vs
(2)
The time required to swim the same distance d downstream is
t_down = d/ v_down = d/ v+ vs
 
        
             
        
        
        
Answer:
Tension in the cable is T = 16653.32 N
Explanation:
Give data:
Cross section Area A = 1.3 m^2
Drag coefficient CD = 1.2
Velocity V = 4.3 m/s
Angle made by cable with horizontal  =30 degree
Density 
  Drag force FD is given as

         
 Drag force = 14422.2 N acting opposite to the motion
As cable made angle  of 30 degree with horizontal  thus horizontal component is take into action to calculate drag force
TCos30 = F_D


T = 16653.32 N
 
        
             
        
        
        
Answer:
a)  V = 1.866 10² V
,  b)   V = 3.424 10⁵ V
, c)   v = 8.1 10⁶ m / s 
Explanation:
a) the potential difference is requested to accelerate the electrons up to 2.7% of the speed of light
            v = 0.027 c
            v = 0.027 3 10⁸
            v = 8.1 10⁶ m / s
for this part we can use the conservation of mechanical energy
starting point. When electrons are at rest
            Em₀ = U = q V
final point. Electrons with maximum speed
           Em_f = K = ½ m v2
           Em₀ = Em_{f}
           e V = ½ m v²
           V = ½ m v² / e
let's calculate
           V = ½  9.1 10⁻³¹ (8.1 10⁶)² / 1.6 10⁻¹⁹
           V = 1.866 10² V
            V = 1866 V
          
b) if this acceleration protons is the mass of the proton is m_{p} = 1.67 10-27
           V = ½ 1.67 10⁻²⁷ (8.1 10⁶)² / 1.6 10⁻¹⁹
            V = 3.424 10⁵ V
            V = 342402 V
c)  
this potential difference should give the protons the same speed as the electrons
              v = 8.1 10⁶ m / s
 
        
             
        
        
        
Answer:
You will hear the note E₆
Explanation:
We know that:
Your speed = 88m/s
Original frequency = 1,046 Hz
Sound speed = 340 m/s
The Doppler effect says that:

Where:
f = original frequency
f' = new frequency
v = velocity of the sound wave
v0 = your velocity
vs = velocity of the source, in this case, the source is the diva, we assume that she does not move, so vs = 0.
Replacing the values that we know in the equation we have:

This frequency is close to the note E₆ (1,318.5 Hz)