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lozanna [386]
2 years ago
5

Burl the painter weighs 600 Newtons. He stands in the exact middle of his stage. There are two scale readings attached to the tw

o cords holding up the stage.
The image shows a painter standing in the middle of a scaffold that is hanging with two ropes on each end. Each rope has a spring scale.

What is the weight measured by each scale?

200 N
300 N
600 N
1200 N
Physics
1 answer:
chubhunter [2.5K]2 years ago
6 0

Answer:

T = 300 N

Explanation:

As we know that the painter is standing at the middle of the scaffold

So here the two ropes will exert same tension on the scaffold

So we will have

T_1 + T_2 = W

also we know

T_1 = T_2

so we will have

2T = W

T = \frac{W}{2}

so tension is half of the weight in both the strings

So it is

T = 300 N

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Which statements can be inferred from the Paleozoic era time scale? There was volcanic activity during the Paleozoic era. Dinosa
Alchen [17]

Answer:

A,C,E

Explanation:

5 0
1 year ago
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A river has a steady speed of vs. A student swims upstream a distance d and back to the starting point. (a) If the student can s
andre [41]

he speed of the student relative to shore is

v_ up = v- vs

v _down = v+ vs

The time required to travel distance d upstream
is

t_up = d/ v_up = d/ v- vs

(2)

The time required to swim the same distance d downstream is

t_down = d/ v_down = d/ v+ vs

6 0
1 year ago
Oceanographers use submerged sonar systems, towed by a cable from a ship, to map the ocean floor. In addition to their downward
KATRIN_1 [288]

Answer:

Tension in the cable is T = 16653.32 N

Explanation:

Give data:

Cross section Area A = 1.3 m^2

Drag coefficient CD = 1.2

Velocity V = 4.3 m/s

Angle made by cable with horizontal  =30 degree

Density \rho \ of\  water= 1000 kg/m3

 Drag force FD is given as

F_{D} = \fracP{1}{2} \rho v^{2} C_{D} A

        = 0.5\times 1000\times 4.32\times  1.2\times 1.3

Drag force = 14422.2 N acting opposite to the motion

As cable made angle  of 30 degree with horizontal  thus horizontal component is take into action to calculate drag force

TCos30 = F_D

T = \frac{F_D}{cos30}

T =\frac{ 14422.2}{cos 30}

T = 16653.32 N

7 0
2 years ago
An x-ray tube is an evacuated glass tube that produces electrons at one end and then accelerates them to very high speeds by the
laila [671]

Answer:

a)  V = 1.866 10² V ,  b)   V = 3.424 10⁵ V , c)   v = 8.1 10⁶ m / s

Explanation:

a) the potential difference is requested to accelerate the electrons up to 2.7% of the speed of light

           v = 0.027 c

           v = 0.027 3 10⁸

           v = 8.1 10⁶ m / s

for this part we can use the conservation of mechanical energy

starting point. When electrons are at rest

           Em₀ = U = q V

final point. Electrons with maximum speed

          Em_f = K = ½ m v2

          Em₀ = Em_{f}

          e V = ½ m v²

          V = ½ m v² / e

let's calculate

          V = ½  9.1 10⁻³¹ (8.1 10⁶)² / 1.6 10⁻¹⁹

          V = 1.866 10² V

           V = 1866 V

         

b) if this acceleration protons is the mass of the proton is m_{p} = 1.67 10-27

          V = ½ 1.67 10⁻²⁷ (8.1 10⁶)² / 1.6 10⁻¹⁹

           V = 3.424 10⁵ V

           V = 342402 V

c)   this potential difference should give the protons the same speed as the electrons

             v = 8.1 10⁶ m / s

5 0
2 years ago
Driving your Ferrari through the Italian countryside at a speedy 88 m/s, you approach an opera diva singing a high C (1,046 Hz).
MrRissso [65]

Answer:

You will hear the note E₆

Explanation:

We know that:

Your speed = 88m/s

Original frequency = 1,046 Hz

Sound speed = 340 m/s

The Doppler effect says that:

f' = \frac{v \pm v0 }{v \mp vs}*f

Where:

f = original frequency

f' = new frequency

v = velocity of the sound wave

v0 = your velocity

vs = velocity of the source, in this case, the source is the diva, we assume that she does not move, so vs = 0.

Replacing the values that we know in the equation we have:

f' = \frac{340 m/s + 88m/s}{340 m/s} *1,046 Hz = 1,316.73 Hz

This frequency is close to the note E₆ (1,318.5 Hz)

7 0
1 year ago
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