Question

Assume that wave #1 has a wavelength of 699 nm. Calculate the frequency and energy of the wave (show your work).

Answer 1

Answer :  The frequency of photon is, $4.29\times 10^{14}Hz$  and energy of wave is $2.84\times 10^{-19}J$

Explanation : Given,

Wavelength of wave = $699nm=699\times 10^{-9}m$

First we have to calculate the frequency of wave.

Formula used :

$\nu=\frac{c}{\lambda}$

where,

$\nu$ = frequency of wave

$\lambda$ = wavelength of wave

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$\nu=\frac{3\times 10^8m/s}{699\times 10^{-9}m}$

$\nu=4.29\times 10^{14}s^{-1}=4.29\times 10^{14}Hz$ $(1Hz=1s^{-1})$

The frequency of wave is, $4.29\times 10^{14}Hz$

Now we have to calculate the energy of wave.

Formula used :

$E=h\times \nu$

where,

$\nu$ = frequency of wave

h = Planck's constant = $6.626\times 10^{-34}Js$

Now put all the given values in the above formula, we get:

$E=(6.626\times 10^{-34}Js)\times (4.29\times 10^{14}s^{-1})$

$E=2.84\times 10^{-19}J$

Thus, the energy of wave is $2.84\times 10^{-19}J$

Answer 2

Answers are inside of the boxes