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Lelechka [254]
2 years ago
4

At constant temperature the pressure on a 10.0 liter sample of gas is changed from 1.00 atm to 1140 torr. What is the new volume

of the gas sample?
Chemistry
1 answer:
Arada [10]2 years ago
4 0

Answer:

6.66 L

Explanation:

Boyle's Law:

P1V1 = P2V2

As we know that 1 atm = 760 torr

Substitute:  

(10.0 L) (760 torr) = (V2) (1140 torr);

Solving, V2 = 6.66 L.

You might be interested in
A 103.8g sample of nitric acid solution that is 70.0% HNO3 contains by mass
soldi70 [24.7K]
w/w percentage <span>
               = mass of the pure compound / total mass of the sample x 100%

70% HNO₃ contains by mass means every 100 g of sample has 70 g of HNO₃.</span><span>

The mass of solution = 103.8 g
Hence the mass of HNO₃ = 103.8 g x 70%</span><span>
                                         = 103.8 g x (70 / 100)
<span>                                         = 72.66 g = 72.7 g.</span></span>
3 0
2 years ago
Albus Dumbledore provides his students with a sample of 19.3 g of sodium sulfate. How many oxygen atoms are in this sample
Dimas [21]

Answer:

<em>3.27·10²³ atoms of O</em>

Explanation:

To figure out the amount of oxygen atoms in this sample, we must first evaluate the sample.

The chemical formula for sodium sulfate is <em>Na₂SO₄, </em>and its molar mass is approximately 142.05\frac{g}{mol}.

We will use stoichiometry to convert from our mass of <em>Na₂SO₄ </em>to moles of <em>Na₂SO₄</em>, and then from moles of <em>Na₂SO₄ </em>to moles of <em>O </em>using the mole ratio; then finally, we will convert from moles of <em>O </em>to atoms of <em>O </em>using Avogadro's constant.

19.3g <em>Na₂SO₄</em> · \frac{1 mol Na^2SO^4}{142.05g Na^2SO^4} · \frac{4 mol O}{1 mol Na^2SO^4} ·\frac{6.022x10^2^3}{1 mol O}

After doing the math for this dimensional analysis, you should get a quantity of approximately <em>3.27·10²³ atoms of O</em>.

3 0
2 years ago
Luis is helping his parents paint a border around the walls of a room. He uses a stencil to repeat the same design on each wall
iren [92.7K]

Answer:

Polymerization.

Explanation:

Polymerization can be defined as a type of chemical reaction in which molecules that are relatively small in size chemically combine to form a huge chain of molecules.

Simply stated, polymerization refers to a chemical reaction where two or more smaller molecules react to produce larger molecules of the same network or repetitive structural units.

In polymerization, the relatively small molecules are generally referred to as monomers while the larger molecules they produce are known as polymers.

Polymerization is given by the chemical formula;

nA -----> A(n).

In this scenario, Luis uses a stencil to repeat the same design on each wall to form one long grapevine with a bunch of grapes every foot along its length.

Hence, the type of chemical reaction this best model is polymerization because it involved repeating the same design (monomers) to form a long grapevine with a bunch of grapes (polymers).

5 0
2 years ago
How many grams of CaF2 are present in 1.25 L of a 0.15 M solution of CaF2? How do I find the grams I am confused on that part?
dybincka [34]

Answer:

Mass = 14.64 g

Explanation:

Given data:

Volume of solution = 1.25 L

Molarity of Solution = 0.15 M

Mass of CaF₂ = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

We will calculate the number of moles of CaF₂ and then determine the mass by using number of moles.

0.15 M =  number of moles of solute / 1.25 L

number of moles of solute = 0.15 M ×  1.25 L

number of moles of solute = 0.1875 mol/L × L

number of moles of solute = 0.1875 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.1875 mol ×78.07 g/mol

Mass = 14.64 g

7 0
2 years ago
A 0.1025-g sample of copper metal is dissolved in 35 ml of concentrated hno3 to form cu2 ions and then water is added to make a
GalinKa [24]

Molarity is defined as number of moles of solute in 1 L of solution.

Here, 0.1025 g of Cu is reacted with 35 mL of HNO_{3} to produced Cu^{2+} ions.

The balanced reaction will be as follows:

Cu+3HNO_{3}\rightarrow Cu(NO_{3})_{2}+NO_{2}+H_{2}O

From the above reaction, 1 mole of Cu produces 1 mole of Cu^{2+}, convert the mass of Cu into number of moles as follows:

n=\frac{m}{M}

molar mass of Cu is 63.55 g/mol thus,

n=\frac{0.1025 g}{63.55 g/mol}=0.0016 mol

Now, total molarity of solution, after addition of water is 200 mL or 0.2 L can be calculated as follows:

M=\frac{n}{V}=\frac{0.0016 mol}{0.2 L}=0.008 mol/L=0.008 M

Thus, molarity of Cu^{2+} is 0.008 M.



7 0
2 years ago
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