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AnnZ [28]
2 years ago
15

Titin is a spring-shaped elastic protein that attaches to the thick filament and anchors it to the Z-discs of a sarcomere. If ti

tan was denatured, making it straight, it would no longer be able to: a. hold the thick filament in place. b. recoil when stretched and uncoil when the force is removed. c. contract the sarcomere. d. uncoil when stretched and recoil when the force is removed.
Physics
1 answer:
julsineya [31]2 years ago
7 0

Answer:

a. hold the thick filament in place.

Explanation:

Titin is the third most abundant protein in skeletal muscle (after actin and myosin), this protein has a highly elastic potential, and is therefore the protein most responsible for muscle elasticity.

Each titin molecule connects a Z line to the M line of a sarcomere, thus helping to stabilize the position of the thick filament.

So, titin denaturation may result in an inability to hold the thick filament in place.

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Four students were loading boxes of food collected during a food drive. The force that each student exerted while lifting and th
Fudgin [204]

Answer:

it is B

Explanation:

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2 years ago
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Alonzo sprints for 500 meters along a straight track during a race. After crossing the finish line, he to walks back along the t
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450 meters, straight ahead is the answer.
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The standing vertical jump is a good test of an athlete's strength and fitness. The athlete goes into a deep crouch, then extend
SashulF [63]

Answer:

<em>The athlete will rise 1.10 meters off the ground</em>

Explanation:

<u>Vertical Motion</u>

If an object is launched vertically upwards at an initial speed vo, then it will reach a maximum height given by

\displaystyle y_m=\frac{v_o^2}{2g}

The athlete can exert a net force upwards equal to twice his weight. It makes him accelerate upwards at

\displaystyle a=\frac{F_n}{m}=\frac{2W}{m}=2g

The speed at the end of his push can be computed by

v^2=2ay

Replacing the value of a obtained above:

v^2=4gy

where y is the length of this crouch

v^2=4\cdot 9.8\cdot 0.55

v=4.64\ m/s

This is the initial speed of this vertical launch, thus

\displaystyle y_m=\frac{4.64^2}{2\cdot 9.8}

y_m=1.10\ m

5 0
2 years ago
Steam at 0.6 MPa, 200 oC, enters an insulated nozzle with a velocity of 50 m/s. It leaves at a pressure of 0.15 MPa and a veloci
Rudiy27

Answer:

x2 = 0.99

Explanation:

from superheated water table

at pressure p1 = 0.6MPa and temperature 200 degree celcius

h1 = 2850.6 kJ/kg

From energy equation we have following relation

\dot m( h1+\frac{v1^2}{2}+ gz1 )+ Q = \dot m( h2+\frac{v2^2}{2}+ gz1) + W

\dot m( h1+\frac{v1^2}{2}) = \dot m( h2+\frac{v2^2}{2})

h1+\frac{v1^2}{2} = h2+\frac{v2^2}{2}

2850.6 + [\frac{50^2}{2} * \frac{1 kJ/kg}{1000 m^2/S^2}] = h2 +[ \frac{600^2}{2} * \frac{1 kJ/kg}{1000 m^2/S^2}]

h2 = 2671.85 kJ/kg

from superheated water table

at pressure p2 = 0.15MPa

specific enthalpy of fluid hf = 467.13 kJ/kg

enthalpy change hfg = 2226.0 kJ/kg

specific enthalpy of the saturated gas hg = 2693.1 kJ/kg

as it can be seen from above value hf>h2>hg, so phase 2 is two phase region. so we have

quality of steam x2

h2 = hf + x2(hfg)

2671.85 = 467.13 +x2*2226.0

x2 = 0.99

6 0
2 years ago
A car experiences a centripetal acceleration of 4.4 m/s ^2 as ur rounds a corner with a speed of 15 m/s. What is the radius of t
damaskus [11]
The calculation of the centripetal acceleration of an object following a circular path is based on the equation,

                  a = v² / r

where a is the acceleration, v is the velocity, and r is the radius.

Substituting the known values from the given above,

             4.4 m/s² = (15 m/s)² / r

The value of r from the equation is 51.14 m.

Answer: 51.14 m
3 0
2 years ago
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