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ira [324]
2 years ago
6

Yolanda wanted to buy a total of 6 pounds

Mathematics
1 answer:
Maslowich2 years ago
7 0

Answer:

No she didn't

Step-by-step explanation:

Add the total cost of the food and divide by 6. You'll find that she is short

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Kelly joins Powerhouse Gym. The cost is $30 per month and a one-time $100 joining fee. Lisa joins MegaMuscle Gym for $35 per mon
11Alexandr11 [23.1K]

it will take Lisa 11 months to have paid more than Kelly

8 0
2 years ago
A repair bill for a car is $648.45. The parts cost $265.95. The labor cost is $85 per hour. Write and solve an equation to find
zysi [14]

Answer:

( t - p ) /  85x =  h

( t - 265.95 ) /  85x  = h

648.45 - 265.95 / 85x = 3.32h

h = 3.32

Therefore ( t - p ) /  85x =  3.32

Step-by-step explanation:

648.45 - 265.95

282.50 /85

= 3.32 hrs

Finding equation to find hours can be shown as

( t - p ) /  85x =  3.32

How we found equation to find total

Parts = 19 x 14 - 5/100 = 266- 0.05

648.45 - 265.95 = 282.5

282.5/85 = 3.323  near to 3,233529

Labour = 85x  = 17 (5 + x)

Equation = 17(5+ x) + 14(19) - 5/100 = 648.45 where x = 85

Equation = ( 85x x 3  1/3) + 265 - 19/20 = t

3 0
1 year ago
Jacob’s daily tips this work week were $99, $78, $58, $91, $90, and $68. Is Jacob correct in thinking that the mean best represe
alexandr1967 [171]
Jacob is correct in thinking that because the mean represents the average of several quantities
3 0
2 years ago
Read 2 more answers
In each represent the common form of each argument using letters to stand for component sentences, and fill in the blanks so tha
arlik [135]

Answer:

a

           a \to b

         \neg b

         \neg a

b

If  <u>all prime numbers are odd,</u> then <u>2 is  odd</u>.

2 is not odd.

Therefore, it is not the case that all prime numbers are odd.

Step-by-step explanation:

Considering part A

 The  first sentence is  

If all computer programs contain errors, then this program contains an error.

   The second sentence is

This program does not contain an error.

     The third  sentence is

Therefore, it is not the case that all computer programs contain errors.

Now we will use  a and  b  as the letter to denote the component sentences and   \neg a  and \neg b when the component sentences is not the case

So  a =  If all computer programs contain errors

and  

     b =  this program contains an error.

Generally then is represented as \to

Hence the first sentence is denoted as  

         a \to b

The  second sentence is represented as

            \neg b

The  third sentence is represented as

           \neg a

So part a can be represented as

      a \to b

         \neg b

         \neg a

Considering part B

Here the objective is to fill in the blank spaces so that the logic of the sentence in part b is as that in part a

    Now comparing the second statement  a and  b

                "This program does not contain an error" = "2 is not odd" = \neg b

Hence      "this program contains an error." =  "2 is  odd" =  b

     Now comparing the third  statement  a and  b

Therefore, it is not the case that all computer programs contain errors.  

                                                =

     Therefore, it is not the case that all prime numbers are odd  

                                                =

                                                \neg a

Hence

If all computer programs contain errors, = if all prime numbers are odd.= a                

             

             

3 0
2 years ago
The endpoints of JK are J(–25, 10) and K(5, –20). What is the y-coordinate of point L, which divides JK into a 7:3 ratio? a. –16
Andrews [41]

let's say the point dividing JK is say point P, so the JK segment gets split into two pieces, JP and PK

\bf ~~~~~~~~~~~~\textit{internal division of a line segment} \\\\\\ J(-25,10)\qquad K(5,-20)\qquad \qquad \stackrel{\textit{ratio from J to K}}{7:3} \\\\\\ \cfrac{J~~\begin{matrix} P \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} P \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~K} = \cfrac{7}{3}\implies \cfrac{J}{K} = \cfrac{7}{3}\implies3J=7K\implies 3(-25,10)=7(5,-20)\\\\[-0.35em] ~\dotfill

\bf P=\left(\frac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \frac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)\\\\[-0.35em] ~\dotfill\\\\ P=\left(\cfrac{(3\cdot -25)+(7\cdot 5)}{7+3}\quad ,\quad \stackrel{\textit{y-coordinate}}{\cfrac{(3\cdot 10)+(7\cdot -20)}{7+3}}\right) \\\\\\ P=\left( \qquad ,\quad \cfrac{30-140}{10} \right)\implies P=\left(\qquad ,~~\cfrac{-110}{10} \right)\implies P=(\qquad ,\quad -11)

8 0
2 years ago
Read 2 more answers
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