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2 years ago

Fred's total insurance premium is $7,200 annually. His employer pays 60% of the total premium. How much does

Physics

1 answer:

scoray [572]2 years ago

6 0

Answer:

Fred's annual payment = $ 2880

Explanation:

Given that,

The total insurance premium of Fred annually, P = $ 7,200

This premium amount is divided among Fred and his employer.

His employer pays 60 % of the premium and the remaining 40% is paid by Fred annually.

So, the amount paid by Fred is

( 7200/100) x 40 %

= 2880

So, Fred's share of the premium to be paid annually is $2,880

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ExtremeBDS [4]

b) intervalul de timp t3 in care prin fata sa trece vagonul urmator

Sper că am ajutat!

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2 years ago

A roller coaster accelerates from initial velocity of 6.0 m/s to a final velocity of 70 m/s over 4 seconds . what is the acceler

Gre4nikov [31]

A roller coaster accelerates from an initial velocity of 6.0 m/s to a final velocity of 70 m/s over 4 seconds. whats the acceleration

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2 years ago

1. Do alto de uma plataforma com 15m de altura, é lançado horizontalmente um projéctil. Pretende-se atingir um alvo localizado n

sveta [45]

Answer:

(a). The initial velocity is 28.58m/s

(b). The speed when touching the ground is 33.3m/s.

Explanation:

The equations governing the position of the projectile are

$(1).\: x =v_0t$

$(2).\: y= 15m-\dfrac{1}{2}gt^2$

where $v_0$ is the initial velocity.

(a).

When the projectile hits the 50m mark, $y=0$ ; therefore,

$0=15-\dfrac{1}{2}gt^2$

solving for $t$ we get:

$t= 1.75s.$

Thus, the projectile must hit the 50m mark in 1.75s, and this condition demands from equation (1) that

$50m = v_0(1.75s)$

which gives

$\boxed{v_0 = 28.58m/s.}$

(b).

The horizontal velocity remains unchanged just before the projectile touches the ground because gravity acts only along the vertical direction; therefore,

$v_x = 28.58m/s.$

the vertical component of the velocity is

$v_y = gt \\v_y = (9.8m/s^2)(1.75s)\\\\{v_y = 17.15m/s.$

which gives a speed $v$ of

$v = \sqrt{v_x^2+v_y^2}$

$\boxed{v =33.3m/s.}$

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2 years ago

Determine the maximum weight of the bucket that the wire system can support so that no single wire develops a tension exceeding

stellarik [79]

Let there be N number of wires.

Maximum tension a wire can withstand = 100 lb

so, Total tension N wires can withstand = 100 N

now, total tension in N wires = Maximum weight of bucket

100 N = W

so, W = 100N

W is the weight of bucket and 100N is its maximum value.

8 0

2 years ago

A particle with a charge of -1.24 x 10"° C is moving with instantaneous velocity (4.19 X 104 m/s)î + (-3.85 X 104 m/s)j. What is

astra-53 [7]

Answer:

(a) F= 6.68*10¹¹⁴ N (-k)

(b) F =( 6.68*10¹¹⁴ i + 7.27*10¹¹⁴ j ) N

Explanation

To find the magnetic force in terms of a fixed amount of charge q that moves at a constant speed v in a uniform magnetic field B we apply the following formula:

F=q* v X B Formula (1 )

q: charge (C)

v: velocity (m/s)

B: magnetic field (T)

vXB : cross product between the velocity vector and the magnetic field vector

Data

q= -1.24 * 10¹¹⁰ C

v= (4.19 * 10⁴ m/s)î + (-3.85 * 10⁴m/s)j

B =(1.40 T)i

B =(1.40 T)k

Problem development

a) vXB = (4.19 * 10⁴ m/s)î + (-3.85* 10⁴m/s)j X (1.40 T)i =

= - (-3.85*1.4) k = 5.39* 10⁴ m/s*T (k)

1T= 1 N/ C*m/s

We apply the formula (1)

F= 1.24 * 10¹¹⁰ C* 5.39* 10⁴ m/s* N/ C*m/s (-k)

F= 6.68*10¹¹⁴ N (-k)

a) vXB = (4.19 * 10⁴ m/s)î + (-3.85* 10⁴m/s)j X (1.40 T)k =

=( - 5.39* 10⁴i - 5.87* 10⁴j)m/s*T

1T= 1 N/ C*m/s

We apply the formula (1)

F= 1.24 * 10¹¹⁰ C* ( 5.39* 10⁴i + 5.87* 10⁴j) m/s* N/ C*m/s

F =( 6.68*10¹¹⁴ i + 7.27*10¹¹⁴ j ) N

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2 years ago