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laila [671]
2 years ago
10

A wave on a string is described by

Physics
1 answer:
liberstina [14]2 years ago
5 0

Explanation:

A wave on a string is described is given by :

D(x,t)=2\ cm\ sin[(12.57\ rad/m)-(638\ rad/s)t]

The linear density of the string is 5 g/m.

Where

x is in meters and t is in seconds

The general equation of a wave is given by :

y=A\ sin(kx-\omega t)

(2) The speed of the wave in terms of tension is given by :

v=\sqrt{\dfrac{T}{\mu}}

Also, v=\dfrac{\omega}{k}

So, \dfrac{\omega}{k}=\sqrt{\dfrac{T}{\mu}}

T=\dfrac{\mu \omega^2}{k^2}

T=\dfrac{5\times 10^{-3}\times (638)^2}{(12.57)^2}

T = 12.88 N

(3) The maximum displacement of a point on the string is equal to the amplitude of the wave. So, the maximum displacement is 2 cm.

(4) The maximum speed of a point on the string is given by :

v=A\omega

v=0.02\times 638

v = 12.76 m/s

Hence, this is the required solution.

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From the peak of the jump to the surface, the vertical distance is 27 ft.

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Then the total vertical distance is ...

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3 0
2 years ago
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A steel ball bearing with a radius of 1.5 cm forms an image of an object that has been placed 1.1 cm away from the bearing’s sur
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Answer:

Check the explanation

Explanation:

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

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let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

The image is virtual

The image is upright

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

Kindly check the diagram in the attached image below.

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2 years ago
Use what you have learned in the reading to answer the following question. The point of a compass needle points to Earth’s north
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I would say unlimited polarity because the compass’s needle is always attracted to Earth’s north pole.

Good luck to you!
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1 year ago
A car with speed v and an identical car with speed 2v both travel the same circular section of an unbanked road. If the friction
yawa3891 [41]

Answer:

F'=\dfrac{F}{4}

Explanation:

Let m is the mass of both cars. The first car is moving with speed v and the other car is moving with speed 2v. The only force acting on both cars is the centripetal force.

For faster car on the road,

F=\dfrac{mv^2}{r}

v = 2v

F=\dfrac{m(2v)^2}{r}

F=4\dfrac{m(v)^2}{r}..........(1)

For the slower car on the road,

F'=\dfrac{mv^2}{r}............(2)

Equation (1) becomes,

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8 0
2 years ago
A student practicing for a cross country meet runs 250 m in 30 s. What is the average speed
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Answer:8.3m/sec 30 sec,

Explanation:

A student practicing for a track meet, ran 250 m in 30 sec. a. What was her average speed? 250 m = 8.3 m/sec 30 sec.

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