Answer:
acceleration = -15.3g
Explanation:
given data
speed = 6.00 m/s.
thickness = 12
moves the entire = 12.0 cm
solution
we will use here equation that is
v² - u² = 2 × a × s ........................1
here v = 0 is the final velocity and u = 6.0 m/s is initial velocity and s= 0.12 m is the distance covered and a is the acceleration
so we put here value and get acceleration
a =
a =
a = -150 m/s² ( negative sign means it is a deceleration )
and
acceleration in units of g
a =
a = -15.3 g
Answer:
The energy of this particle in the ground state is E₁=1.5 eV.
Explanation:
The energy of a particle of mass <em>m</em> in the <em>n</em>th energy state of an infinite square well potential with width <em>L </em>is:
In the ground state (n=1). In the first excited state (n=2) we are told the energy is E₂= 6.0 eV. If we replace in the above equation we get that:
So we can rewrite the energy in the ground state as:
Finally
Answer:
a) Impulse |J|= 219.4 kgm/s
b) Force F = 2672 N
Explanation:
Given
Height of fall h = 0.50 m
Mass M = 70 kg
Period of collision t = 0.082 s
Solution
The final velocity of the person v is zero since the person will come to rest.
The initial velocity of the person can be calculated by using the "law of conservation of energy".
Initial Kinetic energy = Final potential energy
a) Impulse
J = final momentum - initial momentum
Magnitude of impulse
b) Force
Answer:
0.0367
Explanation:
The loss in kinetic energy results into work done by friction.
Since kinetic energy is given by
KE=0.5mv^{2}
Work done by friction is given as
W= umgd
Where m is the mass of suitacase, v is velocity of the suitcase, g is acceleration due to gravity, d is perpendicular distance where force is applied and u is coefficient of kinetic friction.
Making u the subject of the formula then we deduce that
Substituting v with 1.2 m/s, d with 2m and taking g as 9.81 m/s2 then
Therefore, the coefficient of kinetic friction is approximately 0.0367