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Gala2k [10]
2 years ago
13

Consider applying Newton’s second law to a man riding an elevator (perhaps to calculate his acceleration). show answer Incorrect

Answer Which of the following forces must be considered? Choose all that apply. The force that the man’s feet exert on the floor of the elevator The force of gravity on the elevator The force the elevator cable exerts on the elevator car The force that the man’s head exerts on his neck The force that the elevator floor exerts on the man’s feet The force of gravity on the man
Physics
1 answer:
bija089 [108]2 years ago
7 0

Answer:

The force that the elevator floor exerts on the man’s feet

The force of gravity on the man

Explanation:

Only two force have to consider

1.  Force of gravity on the man

2. Force that the elevator floor exerts on the man's feet

When a man stands on the elevator floor then it apply a normal force on the floor of elevator.We know that from Newtons third law ,it states that every action have it same magnitude but opposite in direction reaction.

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Determine a formula for the maximum height h that a rocket will reach if launched vertically from the Earth's surface with speed
olga55 [171]

Initially, the energies are:

U_{i}=-\frac{G M_{\varepsilon} m}{r_{e}} \\
=K_{i}=\frac{1}{2} m v_{0}^{2}

At final point, the energies are:

U_{f}=-\frac{G M_{\varepsilon} m}{r_{e}+h} \\
K_{f}=\frac{1}{2} m(0)^{2}=0

Using conservation law of energy,

-\frac{G M_{e} m}{r_{e}}+\frac{1}{2} m v_{0}^{2} &=-\frac{G M_{e} m}{r_{\varepsilon}+h} \\
-\frac{G M_{e}}{r_{e}}+\frac{v_{0}^{2}}{2} &=-\frac{G M_{e}}{r_{e}+h} \\
\frac{-2 G M_{e}+r_{e} v_{0}^{2}}{2 r_{e}} &=-\frac{G M_{e}}{r_{e}+h} \\
\frac{r_{e}+h}{G M_{e}} &=\frac{2 r_{e}}{2 G M_{e}-r_{e} v_{0}^{2}}

The equation is further simplified as:

r_{e}+h &=\left(\frac{2 r_{e}}{2 G M_{e}-r_{e} v_{0}^{2}}\right) G M_{e} \\
h &=\frac{2 r_{e} G M_{e}}{2 G M_{e}-r_{e} v_{0}^{2}}-r_{e} \\
&=\frac{2 r_{e} G M_{e}-2 r_{e} G M_{e}+r_{e}^{2} v_{0}^{2}}{2 G M_{e}-r_{e} v_{0}^{2}} \\
& h=\frac{r_{e}^{2} v_{0}^{2}}{2 G M_{e}-r_{e} v_{0}^{2}}

7 0
2 years ago
11. Scientists put a sample of water into a sealed tank. Water can be a solid, liquid, or gas. At first, the water was a liquid.
leva [86]

Answer:

c . slower and started moving in place.

Explanation:

Matter can exist generally in three phases, as a solid, liquid or gas. But it can be transformed from one phase to another by the removal or application of heat energy.

The water was initially in a liquid form in the sealed tank until energy was transferred out of the substance. Thus, this causes a change of state in which the water turns to a solid. Whereby during the process, the molecules of the water moved slowly until they are fixed at a point, and vibrates individually at their individual point.

Therefore the molecules of water moved slower and stated moving in place (i.e vibrating at a point). The water turns to an ice.

3 0
2 years ago
The formula s = 16t2 gives the distance an object falls due to gravity, where s is the distance in feet and t is the time in sec
Georgia [21]
To determine the distance in units of feet of the object falling at a given time, we simply use the relation given above and substitute the given value of time to the function. We do as follows:

s = 16t^2
s = 16 ( 6 )^2
s = 576 feet

The distance of the object from the ground at 6 seconds is 576 ft.
8 0
2 years ago
An object moving at a constant velocity travels 274 m in 23 s. what is its velocity?
svetlana [45]
V= 274 meters / 23 sec

V= 11.91 meters per sec
6 0
2 years ago
Read 2 more answers
A hot air balloon must be designed to support a basket, cords, and one person for a total payload weight of 1300 N plus the addi
RSB [31]

Answer:

r = 4.44 m

Explanation:

 

For this exercise we use the Archimedes principle, which states that the buoyant force is equal to the weight of the dislodged fluid

         B = ρ g V

Now let's use Newton's equilibrium relationship

         B - W = 0

         B = W

The weight of the system is the weight of the man and his accessories (W₁) plus the material weight of the ball (W)

         σ = W / A

         W = σ A

The area of ​​a sphere is

           A = 4π r²

       W = W₁ + σ 4π r²

The volume of a sphere is

           V = 4/3 π r³

Let's replace

     ρ g 4/3 π r³ = W₁ + σ 4π r²

If we use the ideal gas equation

     P V = n RT

    P = ρ RT

    ρ = P / RT

 

    P / RT g 4/3 π r³ - σ 4 π r² = W₁

    r² 4π (P/3RT  r - σ) = W₁

Let's replace the values

     r² 4π (1.01 10⁵ / (3 8.314 (70 + 273)) r - 0.060) = 13000

     r² (11.81 r -0.060) = 13000 / 4pi

     r² (11.81 r - 0.060) = 1034.51

As the independent term is very small we can despise it, to find the solution

       r = 4.44 m

3 0
2 years ago
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