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AfilCa [17]
2 years ago
14

A 2kg block of which material would require 450 joules of thermal energy to increase its temperature by 1 degree Celsius?

Physics
1 answer:
12345 [234]2 years ago
7 0

The block is made of A) Tin, as its specific heat capacity is 0.225 J/(g^{\circ}C)

Explanation:

When an amount of energy Q is supplied to a sample of material of mass m, the temperature of the material increases by \Delta T, according to the following equation :

Q=mC_s \Delta T

where  C_s is the specific heat capacity of the material.

In this problem, we have:

m = 2 kg = 2000 g is the mass of the unknown material

Q = 450 J is the amount of energy supplied to the block

\Delta T = 1^{\circ}C is the change in temperature of the material

Solving the equation for C_s, we can find the specific heat capacity of the unknown sample:

C_s = \frac{Q}{m \Delta T}=\frac{450}{(2000)(1)}=0.225 J/(g^{\circ}C)

And by comparing with tabular values, we can find that this value is approximately the specific heat capacity of tin.

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

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Nostrana [21]

Answer: Part 1: Propellant Fraction (MR) = 8.76

Part 2: Propellant Fraction (MR) = 1.63

Explanation: The Ideal Rocket Equation is given by:

Δv = v_{ex}.ln(\frac{m_{f}}{m_{e}} )

Where:

v_{ex} is relationship between exhaust velocity and specific impulse

\frac{m_{f}}{m_{e}} is the porpellant fraction, also written as MR.

The relationship v_{ex} is: v_{ex} = g_{0}.Isp

To determine the fraction:

Δv = v_{ex}.ln(\frac{m_{f}}{m_{e}} )

ln(MR) = \frac{v}{v_{ex}}

Knowing that change in velocity is Δv = 9.6km/s and g_{0} = 9.81m/s²

<u>Note:</u> Velocity and gravity have different measures, so to cancel them out, transform km in m by multiplying velocity by 10³.

<u />

<u>Part 1</u>: Isp = 450s

ln(MR) = \frac{v}{v_{ex}}

ln(MR) = \frac{9.6.10^{3}}{9.81.450}

ln (MR) = 2.17

MR = e^{2.17}

MR = 8.76

<u>Part 2:</u> Isp = 2000s

ln(MR) = \frac{v}{v_{ex}}

ln (MR) = \frac{9.6.10^{3}}{9.81.2.10^{3}}

ln (MR) = 0.49

MR = e^{0.49}

MR = 1.63

8 0
2 years ago
The U.S. Department of Energy had plans for a 1500-kg automobile to be powered completely by the rotational kinetic energy of a
navik [9.2K]

Answer:

230

Explanation:

\omega = Rotational speed = 3600 rad/s

I = Moment of inertia = 6 kgm²

m = Mass of flywheel = 1500 kg

v = Velocity = 15 m/s

The kinetic energy of flywheel is given by

K=\dfrac{1}{2}I\omega^2\\\Rightarrow K=\dfrac{1}{2}6\times 3600^2\\\Rightarrow K=38880000\ J

Energy used in one acceleration

K=\dfrac{1}{2}mv^2\\\Rightarrow K=\dfrac{1}{2}1500\times 15^2\\\Rightarrow K=168750\ J

Number of accelerations would be given by

n=\dfrac{38880000}{168750}\\\Rightarrow n=230.4

So the number of complete accelerations is 230

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2 years ago
A boy uses a slingshot to launch a pebble straight up into the air. The pebble reaches a height of 37.0 m above the launch point
denis-greek [22]

Answer:

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Explanation:

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y_f=v_0t-0.5*g*t^2 We solve for initial speed

v_0=\frac{y_f+0.5gt^2}{t}=\frac{37+4.9*2.3^2}{2.3}=27.4m/s

Now, using the same expression we estimated time to first reach 18.5 m :

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The first time corresponds to the first reach.

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A 2100 kg car starts from rest and accelerates at a rate of 2.6 m/s2 for 4.0 s. Assume that the force acting to accelerate the c
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Then W = 1/2*(2100 kg)*(10.4 m/s)2
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E. Wind shear is the change in wind direction or speed with height in an atmosphere.

Explanation:

7 0
2 years ago
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