Answer:
The most correct option is;
B. 10 km
Explanation:

Where:
y = Distance between the two headlights
d = Aperture of observers eye
λ = Wavelength of light
L = Distance between the observer and the headlight
Therefore, from the above solution, the distance between the observer and the headlights is 9386.066 km which is approximately 10 km.
Also we have
sinθ = y/L = 1.22 (λ/d)
sinθ = 1.22×10⁻⁴ rad
<h2>Apartment Explosion Reported </h2>
The apartment’s explosion, reportedly caused by a gas leak, produced a violent release of gas and heat. The heat increased the temperature of the air in the room, which means an increase in the air's molecular kinetic energy.
When heat is provided then temperature increases and the molecules of substances move rapidly by increase of kinetic energy (K.E) temperature increases. It is understood that heat increases temperature.
We know that acceleration is change in velocity by time taken for that change.
In this case velocity change is 3.7 m/s
Time taken for this change = 60 ms = 
So acceleration of frog = 
= 61.66 m/
So acceleration of frog is 61.66 m/
o it is evident that frog is capable of remarkable accelerations.
Answer:
a) v = 1.19 m / s
, b) P₁ = 0.922 10⁵ Pa
Explanation:
1) Let's use the fluid continuity equation
Q = A v
The area of a circle is
A = π r2 = π d²/4
v = Q / A = Q 4 / pi d²
v = 0.006 4/π 0.08²
v = 1.19 m / s
2) write Bernoulli's equation, where point 1 is the bladder and point 2 is the urine exit point
P₁ + ½ rho v₁² + rho g y₁ = P₂ + ½ rho v₂² + rho g y₂
The exercise tell us
P₂ = 1.0013 105 Pa
v₁ = 0
y₁ = 1 m
y₂=0
Rho (water) = 1000 kg / m³
P₁ + rho y₁ = P₂ + ½ rho v₂²
P₁ = P₂ + ½ rho v₂² - rho g y₁
P₁ = 1.013 10⁵ + ½ 1000 (1.19)² - 1000 9.8 1
P₁ = 1.013 10⁵ +708.5 - 9800
P₁ = 92208.5Pa
P₁ = 0.922 10⁵ Pa