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Valentin [98]
2 years ago
11

You analyze a sample of a meteorite that landed on Earth and find that 15/16 of a certain type of radioactive atoms have decayed

into the corresponding daughter atom. Calculate the number of half-lives that have occurred.
Physics
1 answer:
jek_recluse [69]2 years ago
7 0

Answer:

The number of half-lives that have occurred are 4.

Explanation:

Formula used for number of half lives :

a=\frac{a_o}{2^n}

where,

a = amount of reactant left after n-half lives

a_o = Initial amount of the reactant

n = number of half lives

a_o=x

a = x-\frac{15}{16}x=\frac{1}{16}x=a

\frac{1}{16}x=\frac{x}{2^n}

2^n=16=2^4

n = 4

The number of half-lives that have occurred are 4.

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A girl rolls a ball up an incline and allows it to return to her. For the angle ! and ball involved, the acceleration of the bal
Musya8 [376]

Answer:

The distance the ball moves up the incline before reversing its direction is 3.2653 m.

The total time required for the ball to return to the child’s hand is 3.2654 s.

Explanation:

When the girl is moving up:

The final velocity (v) = 0 m/s

Initial velocity (u) = 4 m/s

a = -0.25g = -0.25*9.8 = -2.45 m/s². (Negative because it is in opposite of the velocity and also it deaccelerates while going up).

Let time be t  to reach the top.

Using

v = u + a×t

0 = 4 - 2.45*t

t = 1.6327 s

Since, this is the same time the ball will come back. So,

<u>Total time to go and come back = 2* 1.6327 = 3.2654 s </u>

To find the distance, using:

v² = u² + 2×a×s

0² = 4² + 2×(-2.45)×s

s = 3.2653 m

<u>Thus, the distance the ball moves up the incline before reversing its direction is 3.2653 m.</u>

5 0
2 years ago
A 6.0-ohm resistor that obeys Ohm’s Law is connected to a source of variable potential difference. When the applied voltage is d
leva [86]

Is halved. A 6Ω resistor connected to a voltage source which voltage is decreased from 12V to 6V the current passing through the resistor is halved.

The key to solve this problem is applying Ohm's Law V = R I, clearing I from the equation, we obtain I = V/R. Then, the current is directly proportional to the voltage and inversely proportional to the resistance.

V = 12V and R = 6Ω

I = 12V/6Ω = 2A

V = 6V and R = 6Ω

V = 6V/6Ω = 1A

As we can see the current is halved if the voltage descreased from 12V to 6V

5 0
2 years ago
Andrew kicks a ball along a straight path. The ball rolls straight forward for 13.2 meters. Then Andrew kicks the ball straight
hram777 [196]

Answer:

22.7 meters

Explanation:

Let's remind the difference between distance and displacement:

- distance: the total distance travelled by an object in all its paths

- displacement: the different between the final and initial position of the object

In this case, the problem asks to find the distance covered by the ball. This will be the sum of the distances covered by the ball in each part of its motion, therefore:

d=13.2 m+9.5 m=22.7 m

(instead, the displacement will be the difference between the final and initial position of the ball, therefore:

d=13.2 m-9.5 m=3.7 m)

4 0
2 years ago
Una manguera de agua de 1.3 cm de diametro es utilizada para llenar una cubeta de 24 Litros. Si la cubeta se llena en 48 s. A) ¿
Viefleur [7K]

Answer:

We must translate this:

a 1.3 cm diameter water hose is used to fill a 24-liter bucket. If the bucket is filled in 48 s.  

A) What is the speed with which the water leaves the hose?

B) if the diameter of the hose is reduced to 0.63 cm and assuming the same flow, what will be the speed of the water leaving the hose?

A) If the velocity of the water is Xcm/s

and the radius of the hose is equal to half its diameter, so it is 1.3cm/2

Then in one second we can considerate that a cylinder of:

V = pi*(1.3cm/2)^2*X cm^3 of water.

So we have that quantity in one second of flow.

where pi = 3.14

then in 48 seconds, the amount of water in the bucket is:

V = 48*pi*(1.3/2)^2*X = 24 L = 24,000 cm^3

Now we need to solve this for X.

48*3.14*(1.3/2)^2*X = 24000

63.679*x = 24000

x = 24000/63.679 = 376.89

So the velocity of the water is 376 cm per second.

B) if the diameter is 0.64cm, we have the equation:

48*3.14*(0.63/2)^2*x = 24000

14.955*X = 24000

X = 24000/14.955 = 1604.814 cm/s

6 0
2 years ago
A 50kg mass is sitting on a frictionless surface. An unknown constant force pushes the mass for 2 seconds until the mass reaches
Marina CMI [18]

Answer:

75N

Explanation:

a = v/t = 3/2

F = ma = 50(3/2) = 75

3 0
2 years ago
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