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2 years ago

Use the following balanced equation to answer the question below: 2C₇H₁₄+21O₂→14CO₂+ 14H₂O

Chemistry

1 answer:

Ivanshal [37]2 years ago

3 0

Answer:

The answer to your question is: 516 g of water

Explanation:

2 C₇H₁₄ + 21 O₂ → 14 CO₂ + 14 H₂O

8 moles 43 moles

Process

1.- Find the limiting reactant

Ratio theoretical O₂ / C₇H₁₄ = 21 / 2 = 10.5

Ratio experimental O₂ / C₇H₁₄ = 43 / 8 = 5.3

As the ratio diminishes the limiting reactant is O₂.

2.- Calculate the moles of water

21 moles of O₂ ------------- 14 moles of water

43 moles of O₂ ------------ x

x = (43 x 14) / 21

x = 28.67 moles of water

3.- Calculate the grams of water

Molecular mass of water= 18g

18 g ------------------------ 1 mol of water

x ------------------------ 28.67 moles of water

x = (28.67 x 18) / 1

x = 516 g of water

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Identify the Lewis acids and Lewis bases in the following reactions:

postnew [5]

Answer: 1. $H^++OH^-\rightarrow H_2O$ Lewis acid : $H^+$ , Lewis base : $OH^-$

2. $Cl^-+BCl_3\rightarrow BCl_4^-$ Lewis acid : $BCl_3$ , Lewis base : $Cl^-$

3. $K^++6H_2O\rightarrow K(H_2O)_6$ Lewis acid : $K^+$ , Lewis base : $H_2O$

Explanation:

According to the Lewis concept, an acid is defined as a substance that accepts electron pairs and base is defined as a substance which donates electron pairs.

1. $H^++OH^-\rightarrow H_2O$

As $H^+$ gained electrons to complete its octet. Thus it acts as lewis acid. $OH^-$ acts as lewis base as it donates lone pair of electrons to electron deficient specie $H^+$ .

2. $Cl^-+BCl_3\rightarrow BCl_4^-$

As $BCl_3$ is short of two electrons to complete its octet. Thus it acts as lewis acid. $Cl^-$ acts as lewis base as it donates lone pair of electrons to electron deficient specie $BCl_3$ .

3. $K^++6H_2O\rightarrow K(H_2O)_6$

As $K^+$ is short of electrons to complete its octet. Thus it acts as lewis acid. $H_2O$ acts as lewis base as it donates lone pair of electrons to electron deficient specie $K^+$ .

8 0

2 years ago

The volume of a gas at 7.00°c is 49.0 ml. if the volume increases to 74.0 ml and the pressure is constant, what will the tempera

marshall27 [118]

Using charles law
v1/t1=v2/t2
v1=49ml
v2=74
t1=7+273=280k
t2=?
49/280=74/t2
0.175=74/t2 cross multiply
0.175t2=74
t2=74/0.175
t2=422k or 149celcius

8 0

2 years ago

acetaminophen is a stronger acid than methanol, and sodium methoxide is a stronger base than. write an acid base equilibrium rea

torisob [31]

Answer:

The equilibrium shifts to the right that is the forward reaction.

Explanation:

The chemical compound known as "Acetaminophen" is a chemical compound that is generally known to a layman as Paracetamol and it belongs to the drug class known as anagelsics which helps in the treatment of pain or say in the reduction of pain. Acetaminophen has the chemical Formula to be C8H9NO2, with the Molar mass of 151.163 g/mol and Boiling point of 420 °C.

The reaction between Acetaminophen and sodium methoxide gives methanol and acetaminophen sodium salt. Therefore, the acid base equilibrium reaction of these species is given as;

C8H9NO2 + CH3ONa <========> CH3OH + acetaminophen sodium salt.

The equilibrium shifts to the right that is the forward reaction.

8 0

2 years ago

What volume will 6.745g of neon gas occupy at standard temp and pressure?

Thepotemich [5.8K]

First, multiply the mass by the molar mass of neon to find out how many moles of neon there are. Then, multiply by 22.4 to find out how many liters there are.

6.745g Ne x 1 mole Ne/20 g Ne x 22.4 L/1 mole Ne = 7.5544 L

4 0

2 years ago

Read 2 more answers

The rate of disappearance of HCl was measured for the following reaction:

AURORKA [14]

Answer: (a) 0.000083M/s, 0.000069M/s, 0.000052M/s, 0.000034M/s

(b) average reaction rate between t=0.0min to t=430.0min =0.000049M/s

(c) The average rate between t=54.0 and t=215.0min is greater than the average rate between t=107.0 and t=430.0min

Explanation:

Average reaction rate = change in concentration / time taken

(a) after 54mins, t = 54*60s = 3240s

average reaction rate = (1.58 - 1.85)M / (3240 * 0.0)s

= -0.27M/3240

= 0.000083M/s

after 107mins, t = 107*60s = 6420s

average reaction rate = (1.36 - 1.58)M/ (6420 - 3240)s

= -0.22M/3180s

= 0.000069M/s

after 215mins, t = 215*60s = 12900s

average reaction rate = (1.02 - 1.36)M/ (12900 - 6420)s

= -0.34M/6480s

= 0.000052M/s

after 430mins,t = 430*60 = 25800s

average reaction rate = (0.580 - 1.02)M / (25800 - 12900)s

= -0.44M/12900s

= 0.000034M/s

(b) average reaction rate between t=0.0min to t=430.0min

= (0.580 - 1.85)M/ (25800 - 0.0)s

= -1.27M/25800s

=0.000049M/s

= (1.02 - 1.58)M / (12900 - 3240)s

= -0.56M/9660s

= 0.000058M/s

average reaction rate between t=107.0 and t=430.0min

= (0.580 - 1.36)M / (25800 - 6420)s

= 0.78M /19380s

= 0.000040M/s

Therefore the average rate between t=54.0 and t=215.0min is greater than the average rate between t=107.0 and t=430.0min

6 0

2 years ago