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Yanka [14]
2 years ago
4

A 0.272 g sample of a diprotic acid H2X is titrated to the equivalence point. What is the molar mass of H2X if 40.0 mL of 0.400

M NaOH is required. Assume both protons of the acid were titrated. Express your answer in g/mol.
Chemistry
1 answer:
Harrizon [31]2 years ago
6 0

Answer:

The molar mass is 8.50 g/mol.

Explanation:

Let's consider the neutralization between a diprotic acid and NaOH.

H₂X + 2 NaOH ⇄ Na₂X +  2 H₂O

The molar ratio of H₂X to NaOH is 1:2. Then, the moles of H₂X are:

nH_{2}X=2n_{NaOH}=2 \times 40.0 \times 10^{-3} L \times \frac{0.400mol}{L} =0.0320mol

The molar mass of H₂X is:

\frac{0.272g}{0.0320mol} =8.50g/mol

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a 16.0g sample of iron was heated from 0 degrees Celsius o 35.0 degrees Celsius.the iron absorbed 246.4J of energy as heat. what
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Specific heat means the amount heat needed when unit mass of a substrate increase one degree of temperature. So the specific heat = the heat absorbed/(the mass of the substrate * change in temperature) = 264.4/(16*35)=0.472 J/(g*℃)
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A sample of an ideal gas occupies 2.78 x 10^3 mL at 25°C and 760 mm Hg.
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Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}     (At constant temperature and number of moles)

P_1V_1=P_2V_2    (At constant temperature and number of moles)

where,

P_1 = initial pressure of gas = 760 mm Hg

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V_1 = initial volume of gas = 2.78\times 10^3ml

V_2  = final volume of gas = ?

Putting in the values:

760mm Hg\times 2.78\times 10^3ml=475 mm Hg\times V_2

V_2=4.45\times 10^3ml

Thus it will occupy 4.45\times 10^3ml at the same temperature and 475 mm Hg

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Describe a single measurement that you could make that shows that a kettle is less than 100% efficient (providing evidence that
alexgriva [62]

Answer:

As you haven't explained what measurements you took before solving this problem, I will explain the general procedure to evaluate the efficiency of a kettle. I hope it helps you. I´ll send an attachement file with the full answer, since I couldn't write it here.

I assume that the material that is going to be heated in the kettle is water.

1- You have to boil water in it and take the time it takes to its boiling point (in seconds).  

2- You have to evaluate the amount of energy the water absorbed Q with the efficiency formula which I explain in the attachement file.

3- Divide Q by the time it took to bring the water to boiling so you can have the power it consumed.

4- You divide the last value you obtained by the Kettles's power rating.  

5- Multiply the last value by 100 to obtain a percentage value of efficiency.

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7 0
2 years ago
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AveGali [126]

Answer:

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The ternary constant is given by the following equation:

The symbol XiXi, where XX is an extensive property of a homogeneous mixture and the subscript ii identifies a constituent species of the mixture, denotes the partial molar quantity of species ii defined by

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In a multi phase system (in this case, a ternary system), the components resolved give:

M_{i} = M_{i} + C_{xjxk} (1-2x_{i})

and M^{\alpha } = M_{i} + CX_{xjxk}

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