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ICE Princess25 [194]
1 year ago
13

A miner finds a small mineral fragment with a volume of 5.74 cm^3 and a mass of 28.7 g. What is the density of that mineral frag

ment?
Physics
2 answers:
statuscvo [17]1 year ago
8 0
P=M÷V
p=28.7÷5.74
p=5

The density is 5.
Shkiper50 [21]1 year ago
7 0

Explanation:

Density is defined as mass per unit volume.

Mathematically,       d = \frac{m}{V}

where,             d = density

                       m = mass

                       V = volume

It is given that volume is 5.74 cm^{3} and mass is 28.7 g. Then calculate the density as follows.

                d = \frac{m}{V}

                          = \frac{28.7 g}{5.74 cm^{3}}

                          = 5 g/cm^{3}

Therefore, we can conclude that the density of that mineral fragment is 5 g/cm^{3}.

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Answer:

The potential energy has a  maximum when the ball is a time that is half of the time for total travel

Explanation:

Generally potential energy is a the varies directly with the height according to this formula

            PE =mgh

and the ball attains a maximum height when the time is equal to half of the total time taken to travel  

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1 year ago
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A 4.5-m-long wooden board with a 24-kg mass is supported in two places. One support is directly under the center of the board, a
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All the weight of the wooden board is bear by the support located at the centre of the rod, and the other support which is located at the end, will have no reaction force, or 0 reaction force.

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2 years ago
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4. Susan observed that different kinds and amounts of fossils were present in a cliff behind her house. She wondered why changes
posledela
5,10,15,20,25,30, that's how much it should have been
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2 years ago
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Onur drops a basketball from a height of 10\,\text{m}10m10, start text, m, end text on Mars, where the acceleration due to gravi
Doss [256]

Answer:

Explanation:

Given that,

Basket ball is drop from height

H=10m

It is dropped on planet mass

And the acceleration due to gravity on Mars is given as

g= 3.7m/s²

Time taken for the ball to reach the ground

Initial velocity of the body is zero

u=0m/s

Using equation of motion: free fall

H = ut + ½gt²

10 = 0•t + ½ × 3.7 ×t²

10 = 0 + 1.85t²

10 = 1.85t²

Then, t² =10/1.85

t² = 5.405

t = √ 5.405

t = 2.325seconds

So the time the ball spend on the air before reaching the ground is 2.325 seconds

5 0
2 years ago
A particle has a velocity of v→(t)=5.0ti^+t2j^−2.0t3k^m/s.
Makovka662 [10]

Answer:

a)a=5 i+2t j - 6\ t^2k

b)a=\dfrac{1}{24.83}(5i+4j-24k)\ m/s^2

Explanation:

Given that

v(t) = 5 t i + t² j - 2 t³ k

We know that acceleration a is given as

a=\dfrac{dv}{dt}

\dfrac{dv}{dt}=5 i+2t j - 6\ t^2k

a=5 i+2t j - 6\ t^2k

Therefore the acceleration function a will be

a=5 i+2t j - 6\ t^2k

The acceleration at t = 2 s

a= 5 i + 2 x 2 j - 6 x 2² k  m/s²

a=5 i + 4 j -24 k m/s²

The magnitude of the acceleration will be

a=\sqrt{5^2+4^2+24^2}\ m/s^2

a= 24.83 m/s²

The direction of the acceleration a is given as

a=\dfrac{1}{24.83}(5i+4j-24k)\ m/s^2

a)a=5 i+2t j - 6\ t^2k

b)a=\dfrac{1}{24.83}(5i+4j-24k)\ m/s^2

5 0
2 years ago
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