Question

A miner finds a small mineral fragment with a volume of 5.74 cm^3 and a mass of 28.7 g. What is the density of that mineral fragment?

Answer 1

P=M÷V
p=28.7÷5.74
p=5

The density is 5.

Answer 2

Explanation:

Density is defined as mass per unit volume.

Mathematically,       $d = \frac{m}{V}$

where,             d = density

                       m = mass

                       V = volume

It is given that volume is $5.74 cm^{3}$ and mass is 28.7 g. Then calculate the density as follows.

                $d = \frac{m}{V}$

                          = $\frac{28.7 g}{5.74 cm^{3}}$

                          = $5 g/cm^{3}$

Therefore, we can conclude that the density of that mineral fragment is $5 g/cm^{3}$.