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ICE Princess25 [194]

1 year ago

13

A miner finds a small mineral fragment with a volume of 5.74 cm^3 and a mass of 28.7 g. What is the density of that mineral frag

ment?

2 answers:

statuscvo [17]1 year ago

8 0

P=M÷V
p=28.7÷5.74
p=5

The density is 5.

Shkiper50 [21]1 year ago

7 0

Explanation:

Density is defined as mass per unit volume.

Mathematically, $d = \frac{m}{V}$

where, d = density

m = mass

V = volume

It is given that volume is $5.74 cm^{3}$ and mass is 28.7 g. Then calculate the density as follows.

$d = \frac{m}{V}$

= $\frac{28.7 g}{5.74 cm^{3}}$

= $5 g/cm^{3}$

Therefore, we can conclude that the density of that mineral fragment is $5 g/cm^{3}$ .

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<u>Answer:</u>

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<u>Explanation:</u>

Let the east point towards positive X-axis and north point towards positive Y-axis.

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On her way home from work, Brenda drove 20 miles at 60 miles per hour. Due to poor weather conditions, she then reduced her spee

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Answer:

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Now the relationship between wavelength $\lambda$ , frequency $f$ and speed $v$ of the waves is:

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I hope this help

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salantis [7]

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