A survey is taken among customers of a fast-food restaurant to determine preference for hamburger or chicken. Of 200 respondents
1 answer:
Answer:
Hamburger Chicken
Adults 65 60 125
children 55 20 75
120 80 200
a)What is the probability that a randomly selected individual is an adult?
Total no. of adults = 125
Total no. of people 200
The probability that a randomly selected individual is an adult =
b) What is the probability that a randomly selected individual is a child and prefers chicken?
No. of child prefers chicken = 20
The probability that a randomly selected individual is a child and prefers chicken=
c)Given the person is a child, what is the probability that this child prefers a hamburger?
No. of children prefer hamburger = 55
No. of child = 75
The probability that this child prefers a hamburger=
d) Assume we know that a person has ordered chicken, what is the probability that this individual is an adult?
No. of adults prefer chicken = 60
No. of total people like chicken = 80
A person has ordered chicken, the probability that this individual is an adult=
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Answer:
The value that is greater than 45% of the data values is approximately 137.84.
Step-by-step explanation:
The key is transforming values from this distribution to a z-score range and finding the corresponding value using a z-score table.
We are looking for a value x which attains a critical z-score that corresponds to the (100-45)%=55-th percentile:
The critical z value (from z-score table, online) is: -0.12, so:
The value that is greater than 45% of the data values is approximately 137.84.