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Lera25 [3.4K]
2 years ago
4

Some runners train with parachutes that trail behind them to provide a large drag force. These parachutes have a large drag coef

ficient, by design. One model expands to a rectangle 1.8 m square, with a drag coefficient of 1.4. A runner completes a 200 m run at 5.0 m/s with this chute trailing behind. How much thermal energy is added to the air by the drag force?
Physics
1 answer:
nexus9112 [7]2 years ago
8 0

To develop this problem it is necessary to apply the concepts related to the Aerodynamic Drag Force.

By definition the Drag Force is defined as

F_D = \frac{1}{2} \rho A C_D v^2

Where,

A = Area

\rho= Density

C_d = Drag coefficient

v = Velocity

According to our values we have,

A = 1.8*1.8=3.24m^2

C_D = 1.4

V = 5m/s

Replacing we have

F_D = \frac{1}{2} 1.23*3.24*1.4*5^2

F_D = 69.74

By definition we know that the thermal energy is given by the force applied in a given displacement then

W = F*d

W = 69.74*200

W = 13948J

Therefore the thermal energy is added to the air by the drag force is 13.9kJ

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By definition it is known that force equals mass by acceleration. In other words F = m * a. To find the acceleration, you must clear the formula mentioned. Therefore, for a force of 190.08N and a mass of 28 Kg, we have that the acceleration is a = F / m = (190.08) / (28) = 6.79 m / s ^ 2
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Why are we able to use nuclear energy for practical purposes? The reactions are controlled to regulate energy output. The reacti
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If you lived on Saturn, which planets would exhibit retrograde motion like that observed for Mars from Earth? (Select all that a
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Many industries are powered via distant power stations. Calculate the current flowing through a 7,300m long 10. copper power lin
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Answer:

Current, I = 1000 A

Explanation:

It is given that,

Length of the copper wire, l = 7300 m

Resistance of copper line, R = 10 ohms

Magnetic field, B = 0.1 T

\mu_o=4\pi \times 10^{-7}\ T-m/A

Resistivity, \rho=1.72\times 10^{-8}\ \Omega-m

We need to find the current flowing the copper wire. Firstly, we need to find the radius of he power line using physical dimensions as :

R=\rho \dfrac{l}{A}

R=\rho \dfrac{l}{\pi r^2}

r=\sqrt{\dfrac{\rho l}{R\pi}}

r=\sqrt{\dfrac{1.72\times 10^{-8}\times 7300}{10\pi}}

r = 0.00199 m

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The magnetic field on a current carrying wire is given by :

B=\dfrac{\mu_o I}{2\pi r}

I=\dfrac{2\pi rB}{\mu_o}

I=\dfrac{2\pi \times 0.1\times 2\times 10^{-3}}{4\pi \times 10^{-7}}

I = 1000 A

So, the current of 1000 A is flowing through the copper wire. Hence, this is the required solution.

4 0
2 years ago
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