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LuckyWell [14K]
2 years ago
7

Why are we able to use nuclear energy for practical purposes? The reactions are controlled to regulate energy output. The reacti

ons are uncontrolled for maximum energy output. All of the products are fed back into the reaction to keep it going. All of the products are immediately removed to inhibit more reactions.
Physics
2 answers:
yawa3891 [41]2 years ago
7 0

Answer:

it is A) The reactions are controlled to regulate energy output.

Explanation:

I got it right in Edg                                                                                                                                                                      

can I have some yummy brainiest

musickatia [10]2 years ago
5 0

Answer: The reactions are controlled to regulate energy output

Explanation:

Nuclear energy is produced when either two nuclei fuse to produce larger nucleus or a bigger nuclei splits into two smaller nucleus.

Uranium easily splits to produce nuclear energy. The reactions are controlled and energy output can be regulated. Nuclear energy in abundant yet controlled amount is available. Nuclear energy is mostly used in steam turbines to produce electricity.  

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lily's speed would be twice john's speed

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What is the force on a .8 kg peach falling freely in a Yakima orchard
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What type of wave cannot travel in a vacuum
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A sound wave. Because in a vacuum there is no medium in a vacuum. And the only wave that requires a medium to travel through is a sound wave.

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An inclined plane is made out of a short plank of wood. It is used to move a 300N box up onto a tabletop 1m above the floor. Wha
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<em>The purpose of an inclinded plane is to make easier to move objects to a certain height.</em>

The technology behind this is about the Work you need to use to move the object upwards. Basically, when we use an inclined plane, we are splitting the net force, making easier to move. All this means, the force needed to move the objecto up will be lower, due to the inclined plane.

So, if the force needed is lower, then the work is also lower, because the work done is defined as the product between the force applied and the distance traveled.

<em>In addition, if we have a longer inclined plane, that means the force needed is even lower,</em> beacuse the distance is increased, but the Work is the same, because it only depends on the initial and final point.

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You have a light spring which obeys Hooke's law. This spring stretches 2.92 cm vertically when a 2.70 kg object is suspended fro
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(a) 907.5 N/m

The force applied to the spring is equal to the weight of the object suspended on it, so:

F=mg=(2.70 kg)(9.8 m/s^2)=26.5 N

The spring obeys Hook's law:

F=k\Delta x

where k is the spring constant and \Delta x is the stretching of the spring. Since we know \Delta x=2.92 cm=0.0292 m, we can re-arrange the equation to find the spring constant:

k=\frac{F}{\Delta x}=\frac{26.5 N}{0.0292 m}=907.5 N/m

(b) 1.45 cm

In this second case, the force applied to the spring will be different, since the weight of the new object is different:

F=mg=(1.35 kg)(9.8 m/s^2)=13.2 N

So, by applying Hook's law again, we can find the new stretching of the spring (using the value of the spring constant that we found in the previous part):

\Delta x=\frac{F}{k}=\frac{13.2 N}{907.5 N/m}=0.0145 m=1.45 cm

(c) 3.5 J

The amount of work that must be done to stretch the string by a distance \Delta x is equal to the elastic potential energy stored by the spring, given by:

W=U=\frac{1}{2}k\Delta x^2

Substituting k=907.5 N/m and \Delta x=8.80 cm=0.088 m, we find the amount of work that must be done:

W=\frac{1}{2}(907.5 N/m)(0.088 m)^2=3.5 J

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2 years ago
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