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2 years ago

In a certain clock, a pendulum of length L1 has a period T1 = 0.95s. The length of the pendulum

Physics

1 answer:

gulaghasi [49]2 years ago

8 0

Answer:

Ratio of length will be $\frac{L_2}{L_1}=1.108$

Explanation:

We have given time period of the pendulum when length is $L_1$ is $T_1=0.95sec$

And when length is $L_2$ time period $T_2=1sec$

We know that time period is given by

$T=2\pi \sqrt{\frac{L}{g}}$

So $0.95=2\pi \sqrt{\frac{L_1}{g}}$ ----eqn 1

And $1=2\pi \sqrt{\frac{L_2}{g}}$ -------eqn 2

Dividing eqn 2 by eqn 1

$\frac{1}{0.95}=\sqrt{\frac{L_2}{L_1}}$

Squaring both side

$\frac{L_2}{L_1}=1.108$

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Answer:

Explanation:

Given that,

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Using conservation of energy given by the question hint

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Then,

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Now,

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Ef = ½mVf² + m•g•hf

Ef = ½m × 24.8² + m × 9.8 × 0

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Since Ef ≈ Ei, then the rock thrown from the tip of a bridge is independent of the direction of throw

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2 years ago

For a particular reaction, the change in enthalpy is 51kJmole and the activation energy is 109kJmole. Which of the following cou

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2 years ago

A positive point charge Q1 = 2.5 x 10-5 C is fixed at the origin of coordinates, and a negative point charge Q2 = -5.0 x 10-6 C

mario62 [17]

Answer:

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Explanation:

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Consider a location towards the negative side of x-axis beyond the location of charge Q₁

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d = distance between the two charges = 2 m

For the electric field to be zero at the location

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x = - 1.4 m

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2 years ago