a 5.000 kg crate is accelerated from 5.000 m/s to 10.00m/s what is the amount of work needed to accelerate the crate to the near

Question

2 years ago

4

est tenth of a joule

1 answer:

Pie · Answer 1 · 2023-12-04T01:53:54+03:00

The work done on the crate is: 187,500.0 J

Explanation:

According to the work-energy theorem, the work done on an object is equal to the change in kinetic energy of the object. Therefore:

$W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2$

where:

W is the work done

m is the mass of the object

v is the final speed

u is the initial speed

For the crate in this problem, we have:

m = 5,000 kg is the mass

u = 5.0 m/s is the initial speed

v = 10.0 m/s is the final speed

Substituting, we find the work done:

$W=\frac{1}{2}(5000)(10)^2-\frac{1}{2}(5000)(5)^2=187,500.0 J$

Learn more about work:

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