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GenaCL600 [577]
2 years ago
6

The oxidation of an unsaturated fatty acid leads to the production of fewer atps than a saturated fatty acid with the same numbe

r of carbons because ____
Chemistry
1 answer:
vekshin12 years ago
3 0

Explanation:

Oxidization of Fatty acids produces energy in form of NADH and FADH2 cofactors. We get energy from this oxidation. If there's a a double bond already in place, that's an oxidation so you can't get compensated in terms of FADH2 to create a double bond that was there from the outset.   Therefore, if you have a monounsaturated fatty acid, you'll sacrifice the 1.5 ATP that you'd get from that FADH2. And if it's a polyunsaturated fatty acid, you lose more.

therefore, the double leads to bypassing of 1st oxidation reaction and hence eliminating first FADH product.

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A 0.1064 g sample of a pesticide was decomposed by the action of sodium biphenyl. The liberated Cl- was extracted with water and
Ilya [14]

Answer:

Percentage of an aldrin in the sample is 44.41%.

Explanation:

Cl^-+AgNO_3\rightarrow AgCl+NO_{3}^-

Molarity of the silver nitrate solution = 0.03337 M

Volume of the silver nitrate = 23.28 mL = 0.02328 L

Moles of silver nitrate = n

0.03337 M=\frac{n}{0.02328 L}

n = 0.03337 M\times 0.02328 L=0.0007768 mol

According to reaction 1 mole of silver nitrate recats with 1 moles of chloride ions.

Then 0.0007768 moles of silver nitrate will react with:

\frac{1}{1}\times 0.0007768 mol=0.0007768 mol chloride ions.

In one mole of aldrin there are 6  moles of chloride ions.

Then moles of aldrin containing 0.0007768 moles chloride ions are:

\frac{0.0007768 mol}{6}=0.0001295 mol

Moles of aldrin present in the sample = 0.0001295 mol

Mass of 0.0001295 moles of aldrin present in the sample :

0.0001295 mol × 364.92 g/mol =0.04726 g

Percentage of an aldrin in the sample:

\frac{0.04726 g}{0.1064 g}\times 100=44.41\%

8 0
2 years ago
How much heat is released as the temperature of 25.2 grams of iron is decreased from 72.1°C to 9.8°C? The specific heat of iron
prisoha [69]

Answer:

Q=-697.06\ J

Negative sign says that release of heat.

Explanation:

The expression for the calculation of the heat released or absorbed of a process is shown below as:-

Q=m\times C\times \Delta T

Where,  

\Delta H  is the heat released or absorbed

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass = 25.2 g

Specific heat = 0.444 J/g°C

\Delta T=9.8-72.1\ ^0C=-62.3\ ^0C

So,  

Q=25.2\times 0.444\times -62.3\ J=-697.06\ J

Negative sign says that release of heat.

8 0
2 years ago
The metallic radius of a potassium atom is 231 pm. What is the volume of a potassium atom in cubic meters?
Sauron [17]
1 pm = 10∧-10 cm
Therefore, 230 pm is equivalent to 2.3 ×10∧-8 cm.
Atom is in the shape of a sphere,
The volume of a sphere is given by 4/3πr³
Thus, volume of the atom = 4/3π( 2.3 ×10∧-8)³
                                          = 4/3 (3.142 ×12.167×10∧-24
                                           = 5.096 ×10∧-23 cm³
but 1m³= 1000000cm³
Therefore, the volume of the atom = 5.096 ×10∧-29 m³
8 0
2 years ago
Consider the hypothetical atom x. if the molecular formula for lithium carbonate is li2co3 and the formula of x chloride is xcl3
eduard
First step is to determine the valency of each of x and CaCO3 from the given compounds:

1- As for Li2CO3: we can deduce that the valency of lithium is one while that of CO3 is two

2- As for XCl3: we can deduce that the valency of chlorine is one while that of X is three

Second step is to write the required compound: 
X : CO3  (elements involved)
3 : 2        (write the valency of each)
Then write the positive ion (X) followed by the valency of the negative ion (2) and then the negative ion (CO3) followed by the valency of the positive ion (3).
The final x carbonate is written as: X2(CO3)3
7 0
2 years ago
The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in diethyl et
Molodets [167]

Answer:

Explanation:

The vapor pressure of diethyl ether (ether) is 463.57 mm Hg at 25 °C. A nonvolatile, nonelectrolyte that dissolves in diethyl ether is aspirin. Calculate the vapor pressure of the solution at 25 °C when 14.88 grams of aspirin, C9H8O4 (180.1 g/mol), are dissolved in 269.2 grams of diethyl ether. diethyl ether = CH3CH2OCH2CH3 = 74.12 g/mol.

mol of C4H10O = mass of C4H10O / molar mass of C4H10O

= 242.1 g / 74.12 g/mol

= 3.266 mol

mol of C9H8O4 = mass of C9H8O4 / molar mass of C9H8O4

= 10.33 g / 180.1 g/mol

= 0.05736 mol

mole fraction of C4H10O,

X = mole of CHH1O0 / total mol

= (3.266)/(3.266 + 0.05736)

= 0.9827

now use:

P = Po*X

P = 463.57 * 0.9827

= 455.6 mm Hg

3 0
2 years ago
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