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1 year ago

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A graph of the net force F exerted on an object as a function of x position is shown for the object of mass M as it travels a ho

rizontal distance 3d . Which expression represents the change in the kinetic energy of the object?

1 answer:

saul85 [17]1 year ago

5 0

The change in kinetic energy is $\Delta K = 3Fd$

Explanation:

According to the work-energy theorem, the work done on an object is equal to the change in kinetic energy of the object. Mathematically:

$W=K_f -K_i= \Delta K$

where :

W is the work done on the object

$K_f$ is the final kinetic energy of the object

$K_i$ is the initial kinetic energy

Also, the work done on an object is (assuming that the force is applied parallel to the motion of the object):

$W=F\Delta x$

where

F is the magnitude of the force

$\Delta x$ is the displacement of the object

In this problem, the force acting on the object is

F

While the displacement is the horizontal distance travelled, so

$\Delta x = 3d$

Therefore, the work done is

$W=(F)(3d)=3Fd$

And so the change in kinetic energy is

$\Delta K = 3Fd$

Learn more about work and kinetic energy:

brainly.com/question/6763771

brainly.com/question/6443626

brainly.com/question/6536722

#LearnwithBrainly

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Answer:

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Explanation:

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You can calculate the torque by using the information about the Force exerted on the door, and the distance to the hinges. You use the following formula:

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You replace the equation (2) into the equation (1), and you solve for α:

$Fd=I\alpha\\\\I=\frac{Fd}{\alpha}$

Finally, you replace the values of all parameters in the previous equation for I:

$I=\frac{(5.00N)(0.800m)}{2.00rad/s^2}=2kgm^2$

The moment of inertia of the door around the hinges is 2 kgm^2

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Answer:

a). same as

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Explanation:

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That is ω = 1 / r

Since the rear wheel has twice the radius of that of the front wheel, therefore real wheel will have less angular speed than the front wheel.

Therefore, the angular speed of the rear wheel is less than the angular speed of the front wheel.

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Light from a monochromatic source shines through a double slit onto a screen 5.00 m away. The slits are 0.180 mm apart. The dark

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Answer:

Wavelength of incident light, $\lambda = 612 nm$

Given:

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slit width, d = 0.180 mm

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Solution:

To calculate the wavelength of the incident light, $\lambda$ :

$\beta = \frac{x\lambda }{d}$

$\lambda = \frac{\beta d}{x}$

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Answer:

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E = 77.78 KJ

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