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ollegr [7]
2 years ago
8

A graph of the net force F exerted on an object as a function of x position is shown for the object of mass M as it travels a ho

rizontal distance 3d . Which expression represents the change in the kinetic energy of the object?
Physics
1 answer:
saul85 [17]2 years ago
5 0

The change in kinetic energy is \Delta K = 3Fd

Explanation:

According to the work-energy theorem, the work done on an object is equal to the change in kinetic energy of the object. Mathematically:

W=K_f -K_i= \Delta K

where :

W is the work done on the object

K_f is the final kinetic energy of the object

K_i is the initial kinetic energy

Also, the work done on an object is (assuming that the force is applied parallel to the motion of the object):

W=F\Delta x

where

F is the magnitude of the force

\Delta x is the displacement of the object

In this problem, the force acting on the object is

F

While the displacement is the horizontal distance travelled, so

\Delta x = 3d

Therefore, the work done is

W=(F)(3d)=3Fd

And so the change in kinetic energy is

\Delta K = 3Fd

Learn more about work and kinetic energy:

brainly.com/question/6763771

brainly.com/question/6443626

brainly.com/question/6536722

#LearnwithBrainly

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An astronomy student, for her PhD, really needs to estimate the age of a cluster of stars. Which of the following would be part
LiRa [457]

Answer:

A. plot an H-R diagram for the stars in the cluster.

Explanation:

A star cluster can be defined as a constellation of stars, due to gravitational force, which has the same origin.

The astronomy student would have to plot an H-R diagram for the stars in the cluster and determine the age of the cluster by observing the turn-off point. The turn-off is majorly as a result of gradual depletion of the source of energy of the star. Thus, it projects off the constellation.

4 0
2 years ago
A ray of yellow light ( f = 5.09 × 1014 hz) travels at a speed of 2.04 × 108 meters per second in
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Velocity = fλ

where f is frequency in Hz, and λ is wavelength in meters.

<span>2.04 * 10⁸ m/s =  5.09 * 10¹⁴  Hz   *  λ </span>

<span>(2.04 * 10⁸ m/s) / (5.09 * 10¹⁴  Hz ) = λ </span>

<span>4.007*10⁻⁷  m =  λ </span>

<span>The wavelength of the yellow light = 4.007*10⁻⁷  m<span> </span></span>
6 0
2 years ago
A 1100kg car pulls a boat on a trailer. (a) what total force resists the motion of the car, boat,and trailer, if the car exerts
likoan [24]
Refer to the figure shown below.

m₁ = 1100 kg, the mass of the car
m₂ = 700 kg, the mass of the trailer and boat
F = 1900 N, the driving force acting on the car
N₁ = m₁g,  the normal reaction on the car
N₂ = m₂g, the normal force on the trailer and boat
μN₁ and μN₂ are frictional forces, where  =  kinetic coefficient of friction
T = the force in the hitch between the car and trailer.

Part (a)
Let R₁ = the total force that resists the motion of the car, boat, and trailer.
Because the acceleration is 0.550m/s², therefore
(m₁ + m₂ kg)*(0.55 m/s²) = F
(1100+700 kg)*(0.55 m/s²) = (1900 - R₁) N
990 = 1900 - R
R₁ = 910 N

Answer: The resistive force is 910 N

Part (b)
80% of the resistive forces are experienced by the boat and trailer.
Let the resistive force be R₂.
Then
R₂ = 0.8*R₁ = 728 N
If the tension in the hitch between the car and the trailer is T, then
T - R₂ = m₂(0.55 m/s²)
(T - 728 N) = (700 kg)*(0.55 m/s²)
T - 728 = 385
T = 1113 N

Answer: The force in the hitch is 1113 N

3 0
2 years ago
In the produce section of a supermarket, five pears are placed on a spring scale. The placement of the pears stretches the sprin
tankabanditka [31]

Answer:

The displacement of the spring due to weight is 0.043 m

Explanation:

Given :

Mass m = 2 Kg

Spring constant k = 450 \frac{N}{m}

According to the hooke's law,

  F = -kx

Where F = force, x = displacement

Here,

F = mg         ( g = 9.8 \frac{m}{s^{2} } )

F = 2 \times 9.8 = 19.6 N

Now for finding displacement,

  x = \frac{F}{k}

Here minus sign only represent the direction so we take magnitude of it.

  x = \frac{19.6}{450}

  x = 0.043 m

Therefore, the displacement of the spring due to weight is 0.043 m

8 0
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Vanyuwa [196]

The correct answer is B

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