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Ilya [14]
2 years ago
3

Sam is pushing a cart. How can he make the cart move faster?

Physics
2 answers:
katen-ka-za [31]2 years ago
7 0

D) He can increase the force of his push

This would make it go faster

Taya2010 [7]2 years ago
6 0

Answer:

D

Explanation:

A) He can add weight to the cart.

 If he added weight to the cart it would be harder to push, and probably slow it down.

B) He can push the cart up a ramp.

Pushing the cart up the ramp would require a lot of extra force. Going up a ramp would not make it faster.

C) He can take the wheels off the cart.

taking the wheels off the cart would make it EVEN  harder to move the cart...it would no go faster

D) He can increase the force of his push.

Increasing the force of the push at a speed rate will increase the speed

May i have brainliest please :)

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In the Atwood machine shown below, m1 = 2.00 kg and m2 = 6.05 kg. The masses of the pulley and string are negligible by comparis
Rus_ich [418]
M1 descending
−m1g + T = m1a 

m2 ascending
m2g − T = m2a

this gives :
(m2 − m1)g = (m1 + m2)a 

a = (m2 − m1)g/m1 + m2
   = (5.60 − 2)/(2 + 5.60) x 9.81 
   = = 4.65m/s^2
5 0
2 years ago
Does a fish appear closer or farther from a person wearing swim goggles with an air pocket in front of their eyes than the fish
Sunny_sXe [5.5K]

Answer:

In this case, the index of seawater replacement is 1.33, the index of refraction of air is 1, which is why the angle of replacement is less than the incident angle, so the fish seems to be closer

In the opposite case, when the fish looked at the face of the man, the angle of greater reason why it seems to be further away

Explanation:

This exercise can be analyzed with the law of refraction that establishes that a ray of light when passing from one medium to another with a different index makes it deviate from its path,

      n₁ sin θ₁ = n₂ sin θ₂

where n₁ and n₂ are the refractive indices of the incident and refracted means and the angles are also for these two means.

In this case, the index of seawater replacement is 1.33, the index of refraction of air is 1, which is why the angle of replacement is less than the incident angle, so the fish seems to be closer

1 sin θ₁ = 1.33 sin θ₂

        θ₂ = sin⁻¹ ( 1/1.33 sin θ₁)

In the opposite case, when the fish looked at the face of the man, the angle of greater reason why it seems to be further away

4 0
2 years ago
Springfield's "classic rock" radio station broadcasts at a frequency of 102.1 mhz. what is the length of the radio wave in meter
Mila [183]
The frequency of the radio wave is:
f=102.1 MHz = 102.1 \cdot 10^6 Hz

The wavelength of an electromagnetic wave is related to its frequency by the relationship
\lambda= \frac{c}{f}
where c is the speed of light and f the frequency. Plugging numbers into the equation, we find
\lambda= \frac{3 \cdot 10^8 m/s}{102.1 \cdot 10^6 Hz}= 2.94 m
and this is the wavelength of the radio waves in the problem.
7 0
2 years ago
The flat-bed trailer carries two 1500-kg beams with the upper beam secured by a cable. The coefficients of static friction betwe
Novosadov [1.4K]

Answer:

a) a= 8.33 m/s²,    T = 12.495 N , b)    a = 2.45 m / s²

Explanation:

a) this is an exercise of Newton's second law. As the upper load is secured by a cable, it cannot be moved, so the lower load is determined by the maximum acceleration.

We apply Newton's second law to the lower charge

            fr₁ + fr₂ = ma

The equation for the force of friction is

          fr = μ N

Y Axis

         N - W₁ –W₂ = 0

         N = W₁ + W₂

         N = (m₁ + m₂) g

Since the beams are the same, it has the same mass

        N = 2 m g

We replace

           μ₁ 2mg + μ₂ mg = m a

          a = (2μ₁ + μ₂) g

          a = (2 0.30 + 0.25) 9.8

          a= 8.33 m/s²

Let's look for cable tension with beam 2

          T = m₂ a

          T = 1500 8.33

          T = 12.495 N

b) For maximum deceleration the cable loses tension (T = 0 N), so as this beam has less friction is the one that will move first, we are assuming that the rope is horizontal

           fr = m₂ a₂

           N- w₂ = 0

          N = W₂ = mg

          μ₂ mg = m a₂

          a = μ₂ g

          a = 0.25 9.8

          a = 2.45 m / s²

4 0
2 years ago
in which sealed container would the organisms be able to continuously cycle o2 and co2 gases? a. a jar with a lizard eating a sn
DerKrebs [107]

Correct answer choice is :


C) A jar with snails crawling on living plants


Explanation:


By using the power of sunlight, plants can change carbon dioxide and water into glucose and oxygen in a method described photosynthesis. As photosynthesis needs sunlight, this method only occurs during the day. We usually like to think of this as plants `exhaling in carbon dioxide and `breathing out oxygen. Gas transfer between Alveolar Spaces and Capillaries. The role of the respiratory system is to transfer two gases, oxygen and carbon dioxide. The transfer takes place in the millions of alveoli in the lungs and the capillaries that surround them.


4 0
2 years ago
Read 2 more answers
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