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Sunny_sXe [5.5K]
2 years ago
8

Iodine, I2(s), is more soluble in dichloromethane, CH2Cl2(l), than water because:

Chemistry
1 answer:
Georgia [21]2 years ago
8 0

Answer:

A. the intermolecular forces are similar in both dichloromethane and iodine.

Explanation:

Solubility is determined by the principle , "like dissolves like" .

i.e. , if a compound is polar then it will dissolve in a polar compound only , and

if a compound is non - polar then it will dissolve in a non - polar compound only .

As,

Non polar compounds , have similar interaction , and hence gets dissolved , and similarly ,

polar compounds have similar dipole - dipole interaction , and hence gets dissolved .

From the question ,

Iodine, I₂(s), is more soluble in dichloromethane, CH₂Cl₂(l) , as both are non - polar in nature and hence due to similar interaction , are soluble .

Water is polar in nature and therefore less soluble in Iodine, I₂(s) .

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Write a balanced equation for the reaction of NaCH3COO (also written as NaC2H3O2) and HCl.
hammer [34]
The balance chemical equation is:

NaCH₃COO + HCl → NaCl + HCH₃COO

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2 years ago
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What is the ph of a solution made by combining 157 ml of 0.35 m nac2h3o2 with 139 ml of 0.46 m hc2h3o2? the ka of acetic acid is
ExtremeBDS [4]
The first step is to calculate the molarity of each compound:
final volume of solution = 157 + 139 = 296 mL
molarity of <span>nac2h3o2 = (157 x 0.35) / 296 = 0.1856 molar
molarity of </span><span>hc2h3o2 = (139 x 0.46) / 296 = 0.216 molar

Then, we calculate the pH as follows:
pKa of acetic acid = -log(</span><span>1.75 × 10^-5) = 4.7569
pH = pKa + </span><span> log ([salt] / [acid]) 
     = </span>4.7569 + log(0.1856 / 0.216)
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6 0
2 years ago
A scuba tank contains a mixture of oxygen (O2) and nitrogen (N2) gas. The oxygen has a partial pressure of PO2=5.62MPa. The tota
dmitriy555 [2]

Answer:

21.16 MPa

Explanation:

Partial pressure of oxygen = 5.62 MPa

Total gas pressure = 26.78 MPa

But

Total pressure of the gas= sum of partial pressures of all the constituent gases in the system.

This implies that;

Total pressure of the system = partial pressure of nitrogen + partial pressure of oxygen

Hence partial pressure of nitrogen=

Total pressure of the system - partial pressure of oxygen

Therefore;

Partial pressure of nitrogen= 26.78 - 5.62

Partial pressure of nitrogen = 21.16 MPa

7 0
2 years ago
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Three solutions contain a certain acid. The first contains 10% acid, the second 30%, and the third 50%. A chemist wishes to use
Fittoniya [83]

Answer:

To prepare 50L of 32% solution you need: 11L of 30% solution, 22L of 50% solution and 17L of 10% solution.

Explanation:

A 32% solution of acid means 32L of acid per 100L of solution. As the chemist wants to make a solution using twice as much of the 50% solution as of the 30% solution it is possible to write:

2x*50% + x*30% + y*10% = 50L*32%

<em>130x + 10y = 1600 </em><em>(1)</em>

<em>-Where x are volume of 30% solution, 2x volume of 50% solution and y volume of 10% solution-</em>

Also, it is possible to write a formula using the total volume (50L), thus:

<em>2x + x +y = 50L</em>

<em>3x + y = 50L </em><em>(2)</em>

If you replace (2) in (1):

130x + 10(50-3x) = 1600

100x + 500 = 1600

100x = 1100

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2x = 22L -Volume of 50% solution-

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8 0
2 years ago
93.2 mL of a 2.03 M potassium fluoride (KF) solution
Marrrta [24]

Answer:

1.98 M

Explanation:

Given data

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Step 1: Convert V₁ to liters

We will use the relationship 1 L = 1000 mL.

93.2mL \times \frac{1L}{1000mL} = 0.0932 L

Step 2: Calculate the final volume (V₂)

The final volume is the sum of the initial volume and the volume of water.

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Step 3: Calculate the final concentration (C₂)

We will use the dilution rule.

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