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Karo-lina-s [1.5K]
2 years ago
14

If you hold your arm outstretched with palm upward, the force to keep your arm from falling comes from your deltoid muscle. assu

me that the arm has mass 4 kg and the distances and angles shown in
Physics
1 answer:
Maurinko [17]2 years ago
4 0
Your question seems to be incorrect. Please check below:

What force must the deltoid muscle provide to keep the arm in this position? By what factor does this force exceed the weight of the arm?<span>If you hold your arm outstretched with palm upward, as in (Figure 1) , the force to keep your arm from falling comes from your deltoid muscle. Assume that the arm has mass 4 kg and the distances and angles shown in (Figure 1) . 

F=? 
F/w= ?

The answer is </span><span>339 N</span><span>

</span>
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Susan and Hannah are each riding a swing. Susan has a mass of 25 kilograms, and Hannah has a mass of 30 kilograms. Susan’s swing
Charra [1.4K]

Answer:

Kinetic energy is given by:

K.E. = 0.5 m v²

Susan has mass, m = 25 kg

Velocity with which Susan moves is, v = 10 m/s

Hannah has mass, m' = 30 kg

Velocity with which Hannah moves is, v' = 8.5 m/s

<u>Kinetic energy of Susan:</u>

0.5 m v² = 0.5 × 25 kg × (10 m/s)² = 1250 J

<u>Kinetic energy of Hannah:</u>

0.5 m v'² = 0.5 × 30 kg × (8.5 m/s)² = 1083.75 J

Susan's kinetic energy is <u>1250 J </u>and Hannah's kinetic energy is <u>1083.75 J</u>.

Since kinetic energy is dependent on mass and square of speed. Thus, speed has a greater effect than mass. As it is evident from the above example. Susan has greater kinetic energy due to higher speed than Hannah.

4 0
2 years ago
If the mass of one of two particles is doubled and the distance between them is doubled, the force of attraction between the two
andre [41]
The force of attraction between the two particles will remain the same, because when mass is doubled, force of attraction is doubled. However, when distance between their centers is doubled, then force of  attraction is halved. As such double and half cancel out each other and force of attraction remains the same.
7 0
2 years ago
Read 2 more answers
In a photoelectric effect experiment, electromagnetic radiation containing a finite distribution of wavelengths shines on a meta
Sonja [21]

Answer with Explanation:

a.Intensity of radiation is directly proportional to the frequency of radiation

When the intensity of radiation  increases then the frequency of radiation increases and therefore, the number of photo-electrons emitted by the metal increases.

b.When all  of the wavelength in the radiation are increased by the same amount

We know that  

f=\frac{v}{\lambda}

Frequency is inversely proportional to the wavelength.

Therefore, the frequency decrease .

When the frequency decreases then the number of photo-electrons emitted by the metal decrease.

c.When the work function of the metal is increased  then the gain of kinetic energy decreases .

When energy decreases then the number of photo-electrons emitted by the metal decreases.

3 0
2 years ago
A student has made the statement that the electric flux through one half of a Gaussian surface is always equal and opposite to t
nata0808 [166]

Answer:

E.true only when no charge is enclosed within the Gaussian surface.

Explanation:

Because Gauss’s law states that the net flux of an electric field in a closed surface is directly proportional to the enclosed electric charge.

6 0
2 years ago
Find the time t2 that it would take the charge of the capacitor to reach 99.99% of its maximum value given that r=12.0ω and c=50
defon

Answer:

Explanation:

Given that, .

R = 12 ohms

C = 500μf.

Time t =? When the charge reaches 99.99% of maximum

The charge on a RC circuit is given as

A discharging circuit

Q = Qo•exp(-t/RC)

Where RC is the time constant

τ = RC = 12 × 500 ×10^-6

τ = 0.006 sec

The maximum charge is Qo,

Therefore Q = 99.99% of Qo

Then, Q = 99.99/100 × Qo

Q = 0.9999Qo

So, substituting this into the equation above

Q = Qo•exp(-t/RC)

0.9999Qo = Qo•exp(-t / 0.006)

Divide both side by Qo

0.9999 = exp(-t / 0.006)

Take In of both sodes

In(0.9999) = In(exp(-t / 0.006))

-1 × 10^-4 = -t / 0.006

t = -1 × 10^-4 × - 0.006

t = 6 × 10^-7 second

So it will take 6 × 10^-7 a for charge to reached 99.99% of it's maximum charge

8 0
2 years ago
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