2 years ago

A rhombus has side lengths of 25. What could be the lengths of the diagonals?

Mathematics

1 answer:

Natasha2012 [34]2 years ago

4 0

Answer:

25√2

For the opposite side, the hypotenuse, a rhombus is always divided by a angle bisector. Therefore you use the 45-45-90 theorem

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Ahmed and Gavin are playing both chess and checkers. The probability of Ahmed winning the chess game is 45\%45%45, percent. The

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Simon has 160160160 meters of fencing to build a rectangular garden.

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Graph the line y = kx +1 if it is known that the point M belongs to it: M(1,3)

tigry1 [53]

Answer:

$M(x,y) = (1,3)$ belongs to the line $y = 2\cdot x +1$ . Please see attachment below to know the graph of the line.

Step-by-step explanation:

From Analytical Geometry we know that a line is represented by this formula:

$y=k\cdot x + b$

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$k$ - Slope, dimensionless.

$b$ - y-Intercept, dimensionless.

If we know that $b = 1$ , $x = 1$ and $y = 3$ , then we clear slope and solve the resulting expression:

$k = \frac{y-b}{x}$

$k = \frac{3-1}{1}$

$k = 2$

Then, we conclude that point $M(x,y) = (1,3)$ belongs to the line $y = 2\cdot x +1$ , whose graph is presented below.

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1 year ago

Emma's square patio below has been area=31 sq ft. She decides to decrease one dimension by 1 foot and decreases the other dimens

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Answer:

4.57ft by 1.57 ft

Step-by-step explanation:

We are given that

Emma's square patio has been area=31 sq.ft

One dimension decrease by 1 foot and other dimension decrease by 4 feet.

We have to find the new dimensions of Emma's patio.

Let x be the side of Emma's square patio

We know that

Area of square= $x^2$

$x^2=31$

$x=\sqrt{31}=5.57$ ft

One dimension= $5.57-1=4.57$ ft

other dimension= $5.57-4=1.57 ft$

Hence, the new dimension of Emma's patio is given by

4.57ft by 1.57 ft

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2 years ago