Answer:
The magnitude of the total linear acceleration is 0.27 m/s²
b. 0.27 m/s²
Explanation:
The total linear acceleration is the vector sum of the tangential acceleration and radial acceleration.
The radial acceleration is given by;
where;
a is the angular acceleration and
r is the radius of the circular path
Determine time of the rotation;
Determine angular velocity
ω = at
ω = 1.6 x 0.707
ω = 1.131 rad/s
Now, determine the radial acceleration
The magnitude of total linear acceleration is given by;
Therefore, the magnitude of the total linear acceleration is 0.27 m/s²
b. 0.27 m/s²
The two forces should be equal therefore:
2.10 * Fa = Fa + 2 * F * cos 18
simplifying the right side:
2.10 * Fa = Fa + 1.902 * F
1.10 Fa = 1.902 F
<span>F / Fa = 0.578</span>
Answer:
The drift velocity is 
Explanation:
Given :
Area of metallic wire, 
.
Current through wire , 
Mobile charge density , 
Charge value , 
We need to find drift velocity , 
Now, we know :
Therefore, 
Putting all given values in above equation we get,
Hence, this is the required solution.
Answer:
d = Δv(t2-t1)
Explanation:
Speed is defined as the change of displacement with respect to time. It is expressed as shown;
Speed = change in displacement/change in time
Δv = d/Δt
d = Δv*Δt
d = ΔvΔt
Δt = t2-t1
d = Δv(t2-t1)
Δv is the change in rate of speed
Δt = change in time
The correct expression for the displacement of the car during this motion is d = Δv(t2-t1)
