A 10kg rocket is traveling at 80 m/s when the booster engine applies a constant forward force of 60 N for 3.0 seconds. What impu
1 answer:
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1) weight of the box: 980 N
The weight of the box is given by:
where m=100.0 kg is the mass of the box, and is the acceleration due to gravity. Substituting in the formula, we find
2) Normal force: 630 N
The magnitude of the normal force is equal to the component of the weight which is perpendicular to the ramp, which is given by
where W is the weight of the box, calculated in the previous step, and is the angle of the ramp. Substituting, we find
3) Acceleration:
The acceleration of the box along the ramp is equal to the component of the acceleration of gravity parallel to the ramp, which is given by
Substituting, we find
Answer:
The change in momentum of the ball is 24 kg-m/s
Explanation:
It is given that,
Mass of the ball, m = 1 kg
Initial velocity of the ball, u = -12 m/s (in downwards)
Final velocity of the ball, v = +12 m/s (in upward)
We need to find the change in momentum of the ball.
Initial momentum of the ball,
Final momentum of the ball,
Change in momentum of the ball,
So, the change in momentum of the ball is 24 kg-m/s. Hence, this is the required solution.
Given :
Initial velocity, u = -6 m/s.
Time taken, t = 4 seconds.
Acceleration due to gravity, .( Here negative sign means downward direction )
To Find :
Velocity after 4 seconds.
Solution :
By equation of motion.
v = u + at
Here , a = g.
v = u + gt
v = -6 + (-9.8)×4
v = -6 + (-39.2)
v = -45.2 m/s
Therefore, velocity after 4 seconds is -45.2 m/s.
Hence, this is the required solution.