Answer:
Mass percent of oxygen in Fe(OH)3 = 44.92%
Explanation:Percentage by mass is a way of representing the concentration of an element in a compound. It is calculated as the mass of the element divided by the total mass of the compound, multiplied by 100.
•First find the total mass of the compound
•Molar mass of Fe = 55.85g/mol
•Molar mass of O= 16g/mol
•Molar mass of H=1g/mol
From these we can calculate the molecular mass of Fe(OH)3 = 55.85g/mol + (16g/mol)3 + (1g/mol)3
=55.85g/mol + 48g/mol + 3g/mol
=106.85g/mol
Mass percent of a element = mass of element/total mass of compound × 100
Since we have 3 atoms of oxygen in the compound, the mass of oxygen present is 48g/mol
Mass percent of oxygen= 48g/mol/106.85g/mol × 100
= 0.4492×100= 44.92%
Therefore the mass percent of oxygen in the compound Fe(OH)3 is 44.92%
