Question

As a result of the motion through the magnetic field, a charge in the rod will experience a force F⃗ =qv⃗ ×B⃗ : the usual part of the Lorentz force for charges moving through magnetic fields. This force will push the charge in the rod, and hence this force will be an electromotive force (EMF). For now, we shall say that the force that moves the charges is due to an induced electric field Einduced, which will enable us to calculate the EMF. The fact that there is an induced electric field at all is rather subtle, because there is no closed loop that encloses some changing flux. Therefore, a method that does not involve Faraday's law must be used to solve this motional EMF problem. In fact, this problem is a good introduction to some of the ideas behind Faraday's law. Find the y component of the induced electric field Einduced.

Answer 1

Answer:

The y component of the induced electric field Einduced E = -B v

Explanation:

The force acting on the charge moving with a velocity. v in a magnetic field of strength, B is given by

 F = q v x B

or

simply,      

F = $q\times v\times B sin\theta$

where, $\theta$ is the angle between velocity of charge, q and the magnetic field B.

Also, we know that,

                    F = q E

where, E is the electric field.

Therefore,

$E = \frac{F}{q}$

= $\frac{(q \times v_i \times B_k \times sin 90^{\circ})}{ q}$

E = -B v