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Ad libitum [116K]
2 years ago
10

If the Force exerted by the intern is doubled and the distance is halved, does the done by the intern increase, decrease, or rem

ain the same?
Physics
1 answer:
Jlenok [28]2 years ago
3 0

Remain the same

Explanation:

If the force exerted by the intern is doubled and the distance is halved, the work done by the intern remains the same.

 Work done is the force applied to move a body through a distance.

Work done = F x d

where F is the applied force

            d is the distance moved

Now;

if:

    f = 2f

    d = \frac{1}{2}d

Input the parameter:

 Work done = fxd = 2f x \frac{1}{2}d  = fd

The work done will still remain the same

learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

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A moving sidewalk has a velocity of 1.7m/s north. if a man walks 1.1m/s, how long does it take him to travel 15m north in relati
alexira [117]
I think the answer will be a
3 0
2 years ago
Which one of the following statements concerning kinetic energy is true? a The kinetic energy of an object always has a positive
hodyreva [135]

a The kinetic energy of an object always has a positive value.

Explanation:

The kinetic energy of an object is the energy possessed by an object due to its motion, and it can be calculated as

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

Let's now analyze each statement:

a The kinetic energy of an object always has a positive value. --> TRUE. In fact, the mass of the object is always positive, and the term v^2 is always positive as well, so the kinetic energy is always positive.

b The kinetic energy of an object is directly proportional to its speed. --> FALSE. Looking at the formula, we see that the kinetic energy is proportional to the square of the speed, K\propto v^2.

c The kinetic energy of an object is expressed in watts. --> FALSE. Watts is the units for measuring power, while the kinetic energy is measured in Joules, the units for the energy.

d The kinetic energy of an object is a quantitative measure of its inertia. --> FALSE. The inertia of an object depends only on its mass, not on its speed.

e The kinetic energy of an object is always equal to the object’s potential energy. --> FALSE. The potential energy depends on the altitude from the ground, not from the speed, so the two energies can be different.

Learn more about kinetic energy:

brainly.com/question/6536722

#LearnwithBrainly

8 0
2 years ago
"As the Voyager spacecraft penetrated into the outer solar system, the illumination from the Sun declined. Relative to the situa
____ [38]

Answer:

\frac{I_{2}}{I_{1}} = 0.04

Explanation:

The intensity of a star noticed at a certain distance is inversely proportional to the square of distance. Then:

I_{1}\cdot r_{1}^{2} = I_{2}\cdot r_{2}^{2}

The intensity of the Sun in Jupiter relative to Earth is:

\frac{I_{2}}{I_{1}} = \frac{r_{1}^{2}}{r_{2}^{2}}

\frac{I_{2}}{I_{1}} = \left(\frac{1\,AU}{5.2\,AU} \right) ^{2}

\frac{I_{2}}{I_{1}} = 0.04

3 0
2 years ago
Which of the following statements is/are true? Check all that apply. Check all that apply. Power is the rate at which energy is
AlladinOne [14]

Answer:

True statements:

Power is the rate at which work is done.

Power is the rate at which energy is transformed.

The SI unit of power is watt.

A person is limited in the total work he or she can do by the rate at which energy can be transformed.

Explanation:

The above statements are true.

1. Power is defined as the rate at which work is done.

2. Power is the rate at which energy is transformed. Whenever energy changes its form, or moves from one place to another, the rate at which it makes those changes is described as power.

3. The SI Unit of power is watts.  If 1 joule of energy is converted by an object in 1 second then its power is called one watt.

So, the statement<em> 'the SI unit of power is the horsepower' is</em> false.

4. A person is limited in the total work he or she can do by the rate at which energy can be transformed i.e, his power. He is not only limited by the total energy required.

So, the statement <em>'A person is limited in the total work he or she can do only by the total energy required'</em> is not completely true.

5 0
2 years ago
In the figures, the masses are hung from an elevator ceiling. Assume the velocity of the elevator is constant. Find the tensions
Keith_Richards [23]

The elevator may be moving, but if it is moving at a constant velocity, then the observer viewing the mass-rope system is in an inertial reference frame (non-accelerating) and Newton's laws of motion will apply in this reference frame.

A) Choose the point where the ropes intersect (the black dot above m₁) and set up equations of static equilibrium where the forces are acting on that point:

We'll assume that, because rope 3 is oriented vertically, T₃ also acts vertically.

Sum up the vertical components of the forces acting on the point. We will assign upward acting components as positive and downward acting components as negative.

∑Fy = 0

Eq 1: T₁sin(θ₁) + T₂sin(θ₂) - T₃ = 0

Sum up the horizontal components of the forces acting on the point. We will assign rightward acting components as positive and leftward acting components as negative.

∑Fx = 0

Eq 2: T₂cos(θ₂) - T₁cos(θ₁) = 0

T₃ is caused by the force of gravity acting on m₁ which is very easy to calculate:

T₃ = m₁g

m₁ = 3.00kg

g is the acceleration due to earth's gravity, 9.81m/s²

T₃ = 3.00×9.81

T₃ = 29.4N

Plug in known values into Eq. 1 and Eq. 2:

Eq. 1: T₁sin(38.0) + T₂sin(52.0) - 29.4 = 0

Eq. 2: T₂cos(52.0) - T₁cos(38.0) = 0

We can solve for T₁ and T₂ by use of substitution. First let us rearrange and simplify Eq. 2 like so:

T₂cos(52.0) = T₁cos(38.0)

T₂ = T₁cos(38.0)/cos(52.0)

T₂ = 1.28T₁

Now that we have T₂ isolated, we can substitute T₂ in Eq. 1 with 1.28T₁:

T₁sin(38.0) + 1.28T₁sin(52.0) - 29.4 = 0

Rearrange and simplify, and solve for T₁:

T₁(sin(38.0) + 1.28sin(52.0)) = 29.4

1.62T₁ = 29.4

T₁ = 18.1N

Recall from our previous work:

T₂ = 1.28T₁

Plug in T₁ = 18.1N and solve for T₂:

T₂ = 1.28×18.1

T₂ = 23.2N

B) We'll assume that, because rope 2 is horizontally oriented, T₂ also acts horizontally.

Again, choose the point where the ropes intersect and write equations of static equilibrium involving the forces acting at that point:

Sum up the vertical components of the forces

∑Fy = 0

Eq. 3: T₁sin(θ₃) - T₃ = 0

Sum up the horizontal components of the forces

∑Fx = 0

Eq. 4: T₂ - T₁cos(θ₃) = 0

Right away we can solve for T₃, which is the force of gravity acting on m₂:

T₃ = m₂g, m₂ = 6.00kg, g = 9.81m/s²

T₃ = 6.00×9.81

T₃ = 58.9N

Plug in known values into Eq. 3:

T₁sin(61.0) - 58.9 = 0

We can solve for T₁ now that is is the only unknown value in this equation

0.875T₁ = 58.9

T₁ = 67.3N

Plug in known values into Eq. 4:

T₂ - 67.3cos(61.0) = 0

We can solve for T₂ now that it is the only unknown value in this equation

T₂ = 67.3cos(61.0)

T₂ = 32.6N

6 0
2 years ago
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