Question

A chart labeled table A : effect of height on temperature with initial temperature as 25 degrees Celsius, mass w is 1.0 kilograms and mass c is 5.0 kilograms. The chart is 5 columns and 5 rows. The first column is labeled h in meters with entries 100, 200, 500, 1000. The second column is labeled temperature final in degrees celcius with entries 26.17, 27.34, 30.86, 36.72. The third column is labeled change in temperature in degrees celcius with entries 1.17, 2.34, 5.86, 11.72. The fourth column is labeled gravitational potential energy in kilojoules with no entries. The last column is labeled delta H in kilojoules with no entries.
Use the data provided to calculate the amount of heat generated for each cylinder height. Round your answers to the nearest tenth.

Answer 1

Answer: (1) 4.9 kj

(2) 9.8 kj

(3) 24.5 kj

(4) 49.0 kj

Explanation:

Let's label each cylinder from 1-4

Note that,

Gravitational Potential Energy (PEg) = m × g × h

Where m is mass

g is acceleration due to gravity

h is height

So, calculate the PEg of every cylinder

PEg Cylinder 1 = m × g × h

= 5 × 100 × 9.8 = 4900 J

Which can be converted to, 4900 ÷ 1000 = 4.9 kj  because from the question above, it is in kilojoules (kj)

Cylinder 2 = m × g × h

= 5 × 200 × 9.8 = 9800 J

Which can be converted to, 9800 ÷ 1000 = 9.8 kj

Cylinder 3 = m × g × h

= 5 × 500 × 9.8 = 24,500 J

Which can be converted to,  24500 ÷ 1000 = 24.5 kj

Cylinder 4 = m × g × h

= 5 × 1000 × 9.8 = 49,000 J

Which can be converted to,  49000 ÷ 1000 = 49.0 kj

Thus, the different heat generated  by each cylinder at heights 100 m, 200 m, 500 m and 1000 m (to the nearest tenth) are 4.9 kj, 9.8 kj, 24.5 kj and 49.0 kj respectively.

Answer 2

Answer:

100m: 4.9 kJ

200m: 9.8 kJ

1000m: 49.1 kJ

Explanation:

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