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gayaneshka [121]
1 year ago
8

Competition is likely to occur between which two organisms?

Chemistry
1 answer:
MatroZZZ [7]1 year ago
7 0
<h3>Full question found from another source:</h3>

5. Competition is likely to occur between which two organisms?

A Owls and bacteria

B Deer and butterflies

C Grass and strawberry plants

D Goldfish and rabbits

Answer:

C

Explanation:

Grass and strawberry plants compete for the same resources such as nutrients, water, habitat, and sunlight.

Bacteria and owls rely on completely different resources and mechanisms to survive - bacteria are single cell organisms and owl are complex birds

Deer and butterflies are also are not in competition with eachother - they don't occupy the same habitats, eat the same food or have the same prey.

Goldfish and rabbits will never encounter eachother, given that one lives in water and one lives on land. They do not compete for the same food source or habitat.

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Earth’s early atmosphere was very different from our current atmosphere. Explain the presence or absence of gases in our current
Ivanshal [37]

Answer:

heavier gases - sank to the surface

lighter gases - escaped into space

oxygen - produced through photosynthesis

carbon dioxide - released by volcanoes

Explanation:

Since the formation of the atmosphere on Earth, there has been constant changes in it, gradually leading to the atmosphere that we have nowadays. In the distant past, the atmosphere was much different, and it took lot of time for it to become what it is. The volcanoes with their activity contributed to constant release of carbon dioxide, resulting in the greenhouse effect. The organisms that are able to perform photosynthesis started to release lot of oxygen into the atmosphere, thus setting up better living conditions. The gravity of our planet contributed to the vertical distribution of the gasses, with the heavier being lower, and the lighter ones being further up or released into space.

4 0
2 years ago
If 8.0 g of NH4HS(s) is placed in a sealed vessel with a volume of 1.0 L and heated to 200 ∘C the reaction NH4HS(s) ⇌ NH3(g) + H
PIT_PIT [208]

Answer:

Increasing the volume of the vessel

Explanation:

By the Le Chatelier's principle, if a system in equilibrium suffer a variation that disturbs the equilibriu, the reaction shift in the way to minimize the pertubation and re-establish the equilibrium.

For a variation in pressure, when it increases, the reaction shift for the smallest of gas volume, and if decreases, the reaction will shift for the large gas volume. So, for the reaction given, the products have the large amount of gas, so by decreasing the pressure, more products will be formed, and the amount of NH₄HS will reduce. To decrease the pressure, we can increase the volume of the vessel: for the ideal gas equation (PV= nRT), pressure and volume are indirectly proportional.

7 0
1 year ago
A wave hits a wall as shown. A brick wall with a green arrow pointing to the wall from below and right at a shallow angle. Anoth
Dominik [7]

Answer:

A wave reflection interaction (reflected by the wall)

Explanation:

In a reflection, the propagating wave is bounced off the reflecting surface because the medium of the surface prevents the propagation of the wave through it, such that wave is redirected at an angle equal to the angle of incident on the reflecting surface

Reflection takes place with the different forms of waves, such as sound wave, water waves, and light wave

The objects around us are seen with the aid of reflection of light from a light source such that the reflected light enters our eyes after being reflected on the surface of the object, and the object is seen.

3 0
2 years ago
Read 2 more answers
In a laboratory experiment, the freezing point of an aqueous solution of glucose is found to be -0.325°C, What is the molal conc
Hatshy [7]

0.17 M is the is the molal concentration of this solution

Explanation:

Data given:

freezing point of glucose solution = -0.325 degree celsius

molal concentration of the solution =?

solution is of glucose=?

atomic mass of glucose = 180.01 grams/mole

freezing point of glucose = 146 degrees

freezing point of water = 0 degrees

Kf of glucose = 1.86 °C

ΔT = (freezing point of solvent) - (freezing point of solution)

ΔT = 0.325 degree celsius

molality =?

ΔT = Kfm

rearranging the equation:

m = \frac{0.325}{1.86}

m= 0.17 M

molal concentration of the glucose solution is 0.17 M

3 0
2 years ago
Consider the following equilibrium system: 3O2(g)  2O3(g); Keq = 1 Which equation compares the concentration of oxygen and ozone
Rashid [163]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

 <span>3O2(g) <--> 2O3(g); 

Keq = 1 = [O3]^2/[O2]^3 

So [O2]^3 = [O3]^2 

Thus A) is correct</span>
7 0
1 year ago
Read 2 more answers
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