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nika2105 [10]
2 years ago
11

Suppose that 0.88g of water condenses on a 75.0-g block of iron that is initially at 22 degrees Celsius. If the heat released du

ring condensation goes only to warming the block, what is the final temperature (in degrees Celsius) of the iron block? Assume a constant enthalpy of vaporization for water of 44.0 kJ/mol.
Chemistry
1 answer:
vitfil [10]2 years ago
8 0

Answer:

The final temperature (in degrees Celsius) of the iron block is 85.82 °C

Explanation:

<u>Determine the heat emitted by the condensing water.</u>

qw = 0.88 g H2O  \frac{1 mol H2O}{18.0152 g H2O}  \frac{- 44 kJ}{1 mol H2O}

qw = -2.1492 kJ

<u>Determine the heat absorbed by the iron block</u>

qw = - qw = - (-2.1492 kJ) = 2.1492 kJ

<u>Look up the specific heat for iron. Use the specific heat equation to solve for the final temperature of the iron block.</u>

q = mcΔT

ΔT = q / mc

Temp f = (q / mc) + Temp i

Temp f = 2.1492 x 10^3 J / 75 g (0.449 J/g.°C) + 22 °C

Temp f = 85.82 °C

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Answer:

1.85 × 10⁻⁶

Explanation:

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4 0
2 years ago
If the mass percentage composition of a compound is 72.1% Mn and 27.9% O, its empirical formula is
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Answer:

MnO- Manganese Oxide

Explanation:

Empirical formula: This is the formula that shows the ratio of elements

present in a  

compound.

   

How to determine Empirical formula

1. First arrange the symbols of the elements present in the compound

alphabetically to  determine the real empirical formula. Although, there

are exceptions to this rule, E.g H2So4

2. Divide the percentage composition by the mass number.

3. Then divide through by the smallest number.

4. The resulting answer is the ratio attached to the elements present in

a compound.

           

                                                                              Mn                         O    

                         

% composition                                                      72.1                      27.9    

                       

Divide by mass number                                       54.94                     16  

                                 

                                                                               1.31                      1.74    

                       

Divide by the smallest number                         1.31                      1.31                          

                                                                               1                    1.3

                                                 

The resulting ratio is 1:1

 

Hence the Empirical formula is MnO, Manganese oxide

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